The area of a rectangle garden is 2g^2+34g+140. If the width is 2g+14 what is the length?
1 answer:
We know that
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer is
the length is (g+10)
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer is
the length is (g+10)
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Remark
You must use the sin law to find this.
Multiply through by 12
12 * *12
0.5269 = sin(x)
Now you have to use the inverse of the sine function.
Use your calculator for that
2nd F
sin-1
(0.5269)
= 31.79 degrees. <<<<<< Answer.
There sometimes is a second answer. I don't think there is in this case.