The area of a rectangle garden is 2g^2+34g+140. If the width is 2g+14 what is the length?

Mathematics

1 answer:

ASHA 777 [7]3 years ago

3 0

We know that
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140

using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)

therefore

the length is (g+10)

the answer is
the length is (g+10)

You might be interested in

How many ways can you distribute 4 different balls among 4 different boxes?

Sav [38]

Answer:

16?? not sure.......

6 0

3 years ago

Read 2 more answers

Kelly was asked to determine whether △KLN is congruent to △MNL. She noted that KL ≅ MN, LM ≅ KN, and that the three pairs of cor

Art [367]

Answer:

<h2>Kelly is wrong, with this congruent parts, we can conclude that triangles are congruent.</h2>

Step-by-step explanation:

To demonstrate congruent triangles, we need to use the proper postulates. There are at least 5 postulates we can use.

Angle-Angle-Side Theorem (AAS theorem).
Hypotenuse-Leg Theorem (HL theorem).
Side-Side-Side Postulate (SSS postulate).
Angle-Side-Angle Postulate (ASA postulate).
Side-Angle-Side Postulate (SAS postulate).

In this case, Kelly SAS postulate, because the corresponding sides-angles-sides are congruent, i.e., KL ≅ MN and LM ≅ KN, also, all corresponding angles are congruent.

So, as you can see, only using SAS postulate, the congruency can be demonstrated. (Refer to the image attached to see an example of SAS postulate)