The area of a rectangle garden is 2g^2+34g+140. If the width is 2g+14 what is the length?
1 answer:
We know that
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer is
the length is (g+10)
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer is
the length is (g+10)
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<span>3x − y = 2
y = 3x - 2
x + y = 6
x + 3x - 2 = 6
4x - 2 = 6
4x = 6 + 2
4x = 8
x = </span>
x = 2
Hence, the x co-ordinate is 2.
y = 3x - 2
x + y = 6
x + 3x - 2 = 6
4x - 2 = 6
4x = 6 + 2
4x = 8
x = </span>
x = 2
Hence, the x co-ordinate is 2.