The area of a rectangle garden is 2g^2+34g+140. If the width is 2g+14 what is the length?
1 answer:
We know that
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer is
the length is (g+10)
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer is
the length is (g+10)
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Given:
The area model.
To find:
The area as a sum and area as a product.
Solution:
The four terms of the area model are .
The area as a sum is the sum of all the terms of given area model.
Area as a sum =
=
The area as a product is the factor form of sum of all the terms of given area model.
Area as a product =
=
=
Therefore, the area as a sum is and the area as a product is
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