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alexira [117]
3 years ago
7

There have been incidents of violence at various Olympiads? true or false?

Physics
2 answers:
givi [52]3 years ago
6 0

The correct answer is true

I got the answer right hope it helped

iogann1982 [59]3 years ago
4 0

That's true.

Most of the people who go to Olympic events are mature,
rational, sensible, civilized, mentally balanced people, who
are capable of functioning as members of the human race.

But not all of them.
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A current of 4 amps is running through a circuit with a resistance of 2ohms.What is the voltage.Show working
Rufina [12.5K]
Voltage = current * resistance
V = I*R
I = 4 A
R = 2 ohm
V = 4 A * 2 ohm
= 8 volt
7 0
3 years ago
A soccer player kicks a ball from the ground with a speed of 16 m/s at an angle of 63°.
stepladder [879]

A. Horizontal component: 7.3 m/s

Explanation:

The horizontal component of the velocity is given by:

v_x = v_0 cos \theta

where

v_0 = 16 m/s is the magnitude of the initial velocity

\theta=63^{\circ} is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

v_x = (16 m/s) cos 63^{\circ}=7.3 m/s

B. Vertical component: 14.3 m/s

Explanation:

The vertical component of the velocity is given by:

v_y = v_0 sin \theta

where

v_0 = 16 m/s is the magnitude of the initial velocity

\theta=63^{\circ} is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

v_y = (16 m/s) sin 63^{\circ}=14.3 m/s

6 0
3 years ago
Directions: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about t
Ronch [10]

1. The bowling ball have more potential energy as it sit on top of the building

2.The bowling ball have same potential energy and kinetic energy as it is half way through its fall

3. The bowling ball have more kinetic energy just before it hits the ground

4. The potential energy of the bowling ball as it sits on top of the building is 784J

5. The potential energy of the ball as it is half way through the fall, 20 meters high is 392J

6. The kinetic energy of the ball as it is half way through the fall is 392J

7. The kinetic energy of the ball just before it hits the ground is 784J

Explanation:

Calculating potential energy and kinetic energy for all the instances,

1. ball on top of a 40 meters tall building

Potential energy at the top of building with a height of 40m = mgh

P.E = mgh =2*9.8*40= 784J

At the top pf the building since v=0 kinetic energy is zero

2. half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second

Potential energy when it is half way through fall = mgH

where H represents new height that is equal to 20m

hence P.E=mgH=2*9.8*20= 392J

Kinetic energy  of the ball is \frac{1}{2} mv^{2}  = \frac{1}{2} *2*19.8^{2}=392.04J

3.  Just about to hit the ground from a fall off a building that is 40 meters tall and travelling 28 meters per second.

The potential energy of ball just before it hits the ground = mgh= 2*9.8*0=0J

kinetic energy =\frac{1}{2} mv^{2}= 784J

3 0
3 years ago
How fast will a cart be moving if a force of 200 N is applied to a 50 kg cart for 10 sec?
jeka94

Acceleration = (force) / (mass)

If there is no friction . . .

Acceleration = (200N) / (50 kg) = 4m/s²

Change in speed = (acceleration) x (time) = (4 m/s²) x (10 sec) = 40 m/s

<em>Final speed = (speed of the cart before the force began) + (40 m/s more)</em>

(That's about <em><u>89 mph faster</u></em> than the cart was moving before the force started.)


8 0
3 years ago
Read 2 more answers
How do i know which equation to use for dimensional analysis?
nikitadnepr [17]
You look at the units you want, then try to figure out which units ti multiply by to get the units you have to match the units you want. For example, if you want kg/m^3 and have m/s

You can see that you have a length/time(lets denote it d/t for distance over time) and want mass/volume (lets denote it m/d^3). d/t multiplied by time=d but we want m/d^3 so lets multiply our original d/t by time(t) and mass(m) so d/t(t) (m) =dm. However, we want m/d^3 so we will also have to divide by d^4.

(d/t)(t)(m) /(d^4)=m/d^3 = mass/length^3 =mass/volume which was what we wanted our end result to be.


7 0
4 years ago
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