Answer:
704.25 atm
Explanation:
From the ideal gas equation
PV = nRT
P = nRT/V
Molar volume (V/n) = 34.7 cm^3/mol, n/V = 1/34.7 = 0.0288 mol/cm^3
R = 82.057 cm^3.atm/mol.K
T = 25°C = 25+273 = 298 K
P = 0.0288 × 82.057 × 298 = 704.25 atm
Answer:
Six electrons are transferred in the formation of Al₂O₃.
Explanation:
Aluminium metal and Oxygen react to form Al₂O₃ as,
2 Al + 3/2 O₂ → Al₂O₃
Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms.
So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.
Answer:
I can be your boy bsf : )
Explanation:
im also 15 , chill, takes jokes rlly well(even if it is sarcastic),bit shy sometimes, and I’ll support you all the way
Answer:
New temperature T2 = 707.5 K (Approx.)
Explanation:
Given:
Old pressure P1 = 2 atm
Old temperature T1 = 283 K
New Pressure P2 = 5 atm
Find:
New temperature T2
Computation:
Using Gay-Lussac law;
P1 / T1 = P2 / T2
So,
2 / 283 = 5 / T2
New temperature T2 = 707.5 K (Approx.)
<span>2.28 kg x 213 kJ/kg = 486 kJ = 4.86E+05 J</span>
