How many molecules are in 145 g of aluminum sulfate?

Chemistry

1 answer:

Rina8888 [55]3 years ago

5 0

Answer:2.55 x 10^23 molecules

Explanation:

i had the same question for my class lol, do u go to forest park?

You might be interested in

The equilibrium constant for the reaction

FinnZ [79.3K]

Answer: The concentrations of $Cl_2$ at equilibrium is 0.023 M

Explanation:

Moles of $Cl_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol$

Volume of solution = 1 L

Initial concentration of $Cl_2$ = $\frac{0.14mol}{1L}=0.14M$

The given balanced equilibrium reaction is,

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

Initial conc. 0.14 M 0 M 0M

At eqm. conc. (0.14-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}$

Now put all the given values in this expression, we get :

$4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}$

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of $Cl_2$ at equilibrium is 0.023 M

7 0

3 years ago

Calculate the ph of a solution prepared by dilution 3.0 ml of 2.5 m hcl to a final volume of 100 ml with h2o.

dexar [7]

The pH of the solution after dilution is 1.125.

HCl is hydrochloric acid. It is known by the name muriatic acid. It is among the strong acids. It has a pungent smell and is colorless. It has a molar mass of 36.4 g/mol. It's a common reagent used in pharmaceutical industries. It is also used in other industries such as textile, rubber, and metal.

The volume of HCl added to the solution = 3.0 ml

The molar concentration of HCl = 2.5 M

Let the molar concentration of the solution after dilution is x.

The volume of the diluted solution = 100 ml.

The molar concentration of the solution after dilution is,

$M _{1} V _{2} = M_{2} V _{2}$