A bicyclist was moving at a rate of 8 m/s, and then sped up to 10 m/s. If the cyclist has a mass of 120 kg, how much work was ne
2 answers:
Answer:
Work = 2160 J
Explanation:
As per work energy theorem we know that work done is equal to the change in the kinetic energy of the cyclist.
As the cyclist is initially moving at speed 8 m/s and after some time his speed changes to 10 m/s
So here we can say that
final kinetic energy - initial kinetic energy = work done
now by plug in all values
so work done by cyclist will be 2160 J
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Answer:
The moment of inertia is
Explanation:
From the question we are told that
The frequency is
The mass of the pendulum is
The location of the pivot from the center is
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=>
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Answer: 7.38 km
Explanation: The attachment shows the illustration diagram for the question.
The range of the bomb's motion as obtained from the equations of motion,
H = u(y) t + 0.5g(t^2)
U(y) = initial vertical component of velocity = 0 m/s
That means t = √(2H/g)
The horizontal distance covered, R,
R = u(x) t = u(x) √(2H/g)
Where u(x) = the initial horizontal component of the bomb's velocity = 287 m/s, H = vertical height at which the bomb was thrown = 3.24 km = 3240 m, g = acceleration due to gravity = 9.8 m/s2
R = 287 √(2×3240/9.8) = 7380 m = 7.38 km
