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2 years ago

In order to be sure a grinder used in production is operating properly, what feature of the grinder should be checked daily?

1 answer:

7 0

Fasten pedestal and bench grinders on a solid surface securely.Ensure all the guards are in place and secure before using a grinder.Adjust tool rests to within 3 mm (1/8 in.) of wheels. Never adjust rests while wheels are moving. Work rest height should be on horizontal centre line of the machine spindle.Maintain 6 mm (1/4 in.) wheel exposure with a tongue guard or a movable guard.Check that wheels have blotters on each side.Check the wheel fits properly to the spindle when mounting. If it is loose, get another wheel.Tighten the nuts before you turn the grinder on.Before you plug in the grinder, manually spin the wheel to make sure it is spinning freely.Make sure the cables are not damaged and in good condition.Keep the cables out of the work area.Wear proper personal protective equipment:eye, ear and face protection,metatarsal safety boots, where required,respiratory protection may be required, depending on the work.Wear gloves only where necessary and if there is no risk of entanglement.Stand to one side of the grinder until the wheel reaches operating speed.Bring work into contact with the grinding wheel slowly and smoothly, without bumping.Apply gradual pressure to allow the wheel to warm up evenly. Use only the pressure required to complete a job.Move the work back and forth across the face of the wheel. This movement prevents grooves from forming.Wheels are made only for grinding certain items. Do not grind rough forgings on a small precision grinding wheel. is that enough

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Right hand rule exercise

saveliy_v [14]

Answer:

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2 years ago

The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of 58.0° above the horizo

Jobisdone [24]

(a) 4.0 m/s

We can solve this part just by analyzing the vertical motion of the froghopper.

The initial vertical velocity of the froghopper as it jumps from the ground is given by

$u_y = u_0 sin \theta$ (1)

where

$u_0$ is the takeoff speed

$\theta=58.0^{\circ}$ is the angle of takeoff

The maximum height reached by the froghopper is

h = 58.7 cm = 0.587 m

We know that at the point of maximum height, the vertical velocity is zero:

$v_y = 0$

Since the vertical motion is an accelerated motion with constant (de)celeration $g=-9.8 m/s^2$ , we can use the following SUVAT equation:

$v_y^2 - u_y^2 = 2gh$

Solving for $u_y$ ,

$u_y = \sqrt{v_y^2-2gh}=\sqrt{-2(-9.8)(0.587)}=3.4 m/s$

And using eq.(1), we can now find the initial takeoff speed:

$u_0 = \frac{u_y}{sin \theta}=\frac{3.4}{sin 58.0^{\circ}}=4.0 m/s$

(b) 1.47 m

For this part, we have to analyze the horizontal motion of the froghopper.

The horizontal velocity of the froghopper is

$u_x = u_0 cos \theta = (4.0) cos 58.0^{\circ} =2.1 m/s$

And this horizontal velocity is constant during the entire motion.

We now have to calculate the time the froghopper takes to reach the ground: this is equal to twice the time it takes to reach the maximum height.

The time needed to reach the maximum height can be found through the equation

$v_y = u_y + gt$

Solving for t,

$t=-\frac{u_y}{g}=-\frac{3.4}{9.8}=0.35 s$

So the time the froghopper takes to reach the ground is

$T=2t=2(0.35)=0.70 s$

And since the horizontal motion is a uniform motion, we can now find the horizontal distance covered:

$d=u_x T = (2.1)(0.70)=1.47 m$

7 0

3 years ago

Which involves more work in the scientific sense: moving the boxes and the furniture down from the second floor or up to the fif

Advocard [28]

Answer:

moving the boxes and the furniture up to the fifth floor.

Explanation:

The work done when moving an object up or down is equal to its change of gravitational potential energy:

$W=mg \Delta h$

where

m is the mass of the object

g is the gravitational acceleration

$\Delta h$ is the change in height of the object

We have two opposite situations:

1) when an object is moved upward, $\Delta h$ is positive, so the work done W is positive as well: this means that we need to do work in order to move the object, because we have to "win" the effect of gravity, which pulls the object downward

2) when an object is moved downward, $\Delta h$ is negative, so the work done W is negative as well: this means that we do not need to do work on the object, because it is already done by gravity, which pulls the object downward.

Therefore, more work is done when we are moving the boxes and the furniture up to the fifth floor.

8 0

2 years ago

A. Blue light has higher energy than red light. Write 3 - 4 sentences comparing these electromagnetic waves with respect to the

frosja888 [35]

PART A)

As we know that energy of light depends on its wavelength and frequency as following formula

$E = \frac{hc}{\lambda} = h\nu$

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more

also we know that

$\nu = \frac{c}{\lambda}$

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium

PART B)

Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy

When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.

here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current

So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current

5 0

3 years ago

Read 2 more answers

When would the displacement technique of measuring need to be employed?

Tanzania [10]

Answer:

a is the answer is yes I....

Explanation:

jhjhijbhvfcrsrrtyiiopllmmbcxzaqwryuikmn

5 0

3 years ago