The question is incomplete, the complete question is
When an RL circuit is connected to a battery, what happens to the potential difference across the resistor and the emf across the inductor?
The resistor potential is constant and the inductor emf increases.
The resistor potential is constant and the inductor emf decreases.
The resistor potential is constant and the inductor emf is constant.
The resistor potential decreases and the inductor emf is constant.
The resistor potential decreases and the inductor emf increases.
The resistor potential decreases and the inductor emf decreases.
The resistor potential increases and the inductor emf increases.
The resistor potential increases and the inductor emf is constant.
The resistor potential increases and the inductor emf decreases.
Answer:
The resistor potential increases and the inductor emf decreases.
Explanation:
From Kirchoff's rule, we can easily see that voltage across the inductor decreases steadily in a RL circuit until it finally gets to zero when the circuit is connected to a battery. A graph of the drop in potential across the inductor is attached for more clarity.
The drop shown in figure (b) in the image attached is the drop in potential across the inductor when an RL circuit is connected to a battery.
Answer:
hmax=81ft
Explanation:
Maximum height of the object is the highest vertical position along its trajectory.
The vertical velocity is equal to 0 (Vy = 0)
we isolate th (needed to reach the maximum height hmax)
The formula describing vertical distance is:
So, given y = hmax and t = th, we can join those two equations together:
if we launch a projectile from some initial height h all you need to do is add this initial elevation
Answer:
0.5A
Explanation:
Using ,
R is the resistance (in Ohms)
V is the voltage (in V)
I is the current (in A)
I = 0.5A