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Alenkinab [10]
3 years ago
13

The resistor potential is constant and the inductor emf increases. The resistor potential is constant and the inductor emf decre

ases. The resistor potential is constant and the inductor emf is constant. The resistor potential decreases and the inductor emf is constant. The resistor potential decreases and the inductor emf increases. The resistor potential decreases and the inductor emf decreases. The resistor potential increases and the inductor emf increases. The resistor potential increases and the inductor emf is constant. The resistor potential increases and the inductor emf decreases.

Physics
1 answer:
maks197457 [2]3 years ago
6 0

The question is incomplete, the complete question is

When an RL circuit is connected to a battery, what happens to the potential difference across the resistor and the emf across the inductor?

The resistor potential is constant and the inductor emf increases.

The resistor potential is constant and the inductor emf decreases.

The resistor potential is constant and the inductor emf is constant.

The resistor potential decreases and the inductor emf is constant.

The resistor potential decreases and the inductor emf increases.

The resistor potential decreases and the inductor emf decreases.

The resistor potential increases and the inductor emf increases.

The resistor potential increases and the inductor emf is constant.

The resistor potential increases and the inductor emf decreases.

Answer:

The resistor potential increases and the inductor emf decreases.

Explanation:

From Kirchoff's rule, we can easily see that voltage across the inductor decreases steadily in a RL circuit until it finally gets to zero when the circuit is connected to a battery. A graph of the drop in potential across the inductor is attached for more clarity.

The drop shown in figure (b) in the image attached is the drop in potential across the inductor when an RL circuit is connected to a battery.

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7 0
3 years ago
A loop of wire is in a magnetic field such that its axis is parallel with the field direction. Which of the following would resu
ahrayia [7]

Answer:

All the given options will result in an induced emf in the loop.

Explanation:

The induced emf in a conductor is directly proportional to the rate of change of flux.

emf = -\frac{d \phi}{dt} \\\\where;\\\\\phi \ is \ magnetic \ flux\\\\\phi = BA\ cos \theta

where;

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B is the strength of the magnetic field

θ is the angle between the loop and the magnetic field

<em>Considering option </em><em>A</em>, moving the loop outside the magnetic field will change the strength of the magnetic field and consequently result in an induced emf.

<em>Considering option </em><em>B</em>, a change in diameter of the loop, will cause a change in the magnetic flux and in turn result in an induced emf.

Option C has a similar effect with option A, thus both will result in an induced emf.

Finally, <em>considering option</em> D, spinning the loop such that its axis does not consistently line up with the magnetic field direction will<em> </em>change the angle<em> </em>between the loop and the magnetic field. This effect will also result in an induced emf.

Therefore, all the given options will result in an induced emf in the loop.

4 0
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Explanation:

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<h2><em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u> </u></em></h2>

<em><u>Welcome</u></em><em><u> </u></em>

6 0
3 years ago
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