Explanation:
Mass of bumper cars, 
Initial speed of car A, 
Initial speed of car Z, 
Final speed of car A after the collision, 
We need to find the velocity of car Z after the collision. Let it is equal to
. Using the conservation of momentum as :




So, the velocity of car Z after the collision is (-12 m/s). Hence, this is the required solution.
Answer:
A.) 3605.6 N
B.) 33.7 degree
Explanation:
To find the result force acting on the wing of the airplane, we need to resolve the forces into x and y components
Resolving into x component :
Sum of forces = 3500 - 500 = 3000N
Resolving into y component:
Sum of forces = 2000N
Resultant force Fr = sqrt ( Fx^2 + Fy^2)
Fr = sqrt ( 3000^2 + 2000^2 )
Fr = sqrt ( 9000000 + 4000000 )
Fr = sqrt ( 13000000)
Fr = 3605.6 N
Therefore, resultant force acting on the wing is 3605.6 N
The direction of the vector will be:
Tan Ø = Fy / Fx
Substitute Fx and Fy into the formula
Tan Ø = 2000 / 3000
Tan Ø = 0.66666
Ø = tan^-1(0. 66666)
Ø = 33.7 degree.
Please be determined and being hardworking person do not rely on the other people to make your problems solved
Explanation:
Ok?
An example of a negative incentive for producers is the
sharp increase in production costs. Producers are the one who manage the production
costs and even the production budget. Anything that relates the production
department is entitled to the management of production producers.
There is what we called positive and negative incentives and
both of these can affect consumers and producers. Positive incentives are those
situations which will give a certain outcome that will benefit the producers,
for example, during the peak season there will be a high demand of products, and
this gives the chance of producers to demand a higher price from the consumers,
in this situation, there will be a big chance of increase sales. A sharp increase in production costs is a
loss for the producers. If there will be
an increase in production costs, the budget will be greatly affective and even
though it is not a peak season, there’s a big chance also to increase prices
which we know, consumers are not fond of.
Ammonia because it doesn't have nitrogen