In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

$(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)$

Let

$a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5$

Find the difference between one term and the next

$a_2-a_1=-7-(-10)=3$

$a_3-a_2=-4-(-7)=3$

$a_4-a_3=-1-(-4)=3$

$a_5-a_4=2-(-1)=3$

$a_6-a_5=5-2=3$

The difference between one term and the next is a constant

This constant is the common difference

The sequence graphed is an Arithmetic Sequence

therefore

The first term is $a_1=-10$

The common difference is equal to $d=3$

4 0

3 years ago

A soccer ball is kicked in the air and follow the path h(x)=2x2+1x+6, where x is the time in seconds and h is the height of the

denis-greek [22]

Answer:

You can either factor or use quadratic formula to find where h(x)=0

Step-by-step explanation:

Remember that the ball is on the ground when h(x)=0 since that is the height. There will be two zeros, one is a negative number so would be before you kicked the ball, the other one will be when the ball comes back down.

4 0

3 years ago

Find the domain of the function. (enter your answer using interval notation.) f(x) = x + 3 if x < −1 −2x if |x| ≤ 1 −2 if x &

Ivenika [448]

The domain of the function is the union of all of the "if" parts of the function definition:

... (-∞, -1) ∪ [-1, 1] ∪ (1, ∞) = (-∞, ∞)

4 0

2 years ago