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3 years ago

Identify which table shows a direct variation.

Mathematics

1 answer:

Aneli [31]3 years ago

6 0

The answer is A. <span>Table 1 only the second table should be going by 9.6 but it isn't.</span>

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Please help me with this question

kupik [55]

The answer to this question is B.The new volume will be 8 times the original volume.

6 0

3 years ago

Read 2 more answers

How would you set this problem up to find x?

Elina [12.6K]

Answer:

33x - 13 = 13x + 7

Step-by-step explanation:

If "G" is the midpoint of line FH, then both segments (lines FG and GH) must be the same length. Therefore, to find "x", you can set both segments equal to each other. After doing this, you can simplify and isolate to find "x".

FG = 33x - 13

GH = 13x + 7

FG = GH

33x - 13 = 13x + 7

4 0

2 years ago

Read 2 more answers

Solve the quadratic equation 4x2 − 121 = 0. Verify your answer using a difference-of-squares factoring method.

Alenkasestr [34]

Answer:

Option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

Step-by-step explanation:

Given quadratic equation is $4x^2-121=0$

To write the given quadratic equation by using a difference-of-squares factoring method:

$4x^2-121=0$

The above equation can be written as

$4x^2-11^2=0$

$(2x)^2-11^2=0$

The above equation is in the form of difference-of-squares

Therefore the given quadratic equation can be written in the form of difference-of-squares

by factoring method is $(2x)^2-11^2=0$

$(2x+11)(2x-11)=0$ (which is in the form $a^2-b^2=(a+b)(a-b)$ )

2x+11=0 or 2x-11=0

$x=\frac{-11}{2}$ or $2x=11$

$x=\frac{-11}{2}$ or $x=\frac{11}{2}$

$x=\pm \frac{11}{2}$

Therefore option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

5 0

3 years ago

A mixture of blue paint contains 16 teaspoons of green paint and 4 teaspoons of yellow paint. To make the same shade of blue pai

puteri [66]

20 you would need to be synagogues

3 0

3 years ago

How do you do this problem? I need to know how you found the answer.

Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft$

now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft$

3 0

3 years ago