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3 years ago

Find the length of a.

Mathematics

2 answers:

denis-greek [22]3 years ago

8 0

The answer is 22.2 is correct

inessss [21]3 years ago

6 0

Answer:

22.2

Step-by-step explanation:

Using cosine rule,

$a^{2} = 12^{2} + 15^{2} -2(12)(15)cos110$ °

$a = \sqrt{12^{2} +15^{2}-2(12)(15)cos110 }$

$a = 22.2 (3 sf)$

You might be interested in

The reactants of two reactions are shown.

katovenus [111]

Answer:

The answer to your question is letter B.

Step-by-step explanation:

The correct answer is letter B because both Copper and Iron as reactants have an oxidation number of zero and when they have reacted their oxidation numbers would be different from those.

A redox reaction is a reaction that involves a transfer of electrons from one atom to another and the oxidation numbers of the reactants are different from the oxidation numbers from the products.

4 0

3 years ago

Guys help me out on this one plizzz

evablogger [386]

The term that you want is 5C2*p^2*q^3 representing 2 successes and 3 failures. This term's value is

(5C2)(0.5^5) = 10*0.03125 = 0.3125 = P(2 successes in 5 trials) =31.3%

5 0

3 years ago

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago

Consider triangle GHJ.

bulgar [2K]

we know that

Applying the Pythagorean Theorem

$JG^{2} =HJ^{2}+HG^{2}$

solve for HJ

$HJ^{2}=JG^{2}-HG^{2}$

in this problem we have

$JG=10\ units\\ HG= 5\ units$

Substitute the values in the formula above

$HJ^{2}=10^{2}-5^{2}$

$HJ^{2}=100-25$

$HJ^{2}=75$

$HJ=\sqrt{75}=5\sqrt{3} \ units$

therefore

the answer is the option

B. 5 sq. root 3 units

5 0

3 years ago

Read 2 more answers

a group of 48 students attend a baseball game. the number of women is 12 more than the men. how many men and women attended the

myrzilka [38]

Answer:

First, identify your variables:

Let x = number of men in attendance.

Let y = number of women in attendance.

x + y = 48.

and

y = 12 + x

sub the second equation in for y in the first equation:

x + (12 + x ) = 48.

12 + 2 x = 48

2 x = 36

x = 18

y = 12 + 18

y = 30

8 0

3 years ago