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svlad2 [7]
3 years ago
6

I can't figure out how to solve this

Mathematics
1 answer:
Maslowich3 years ago
3 0
The key: make the base of two side the same,,,
then: for the same base, the exponents are equal.
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2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


3 0
3 years ago
Read 2 more answers
Simplify:-6+{14+2[60-9(1+3)]}
yuradex [85]
1 + 3 = 4;
9 x 4 = 36;
60 - 36 = 24;
2 x 24 = 48;
14 + 48 = 62;
-6 + 62 = 56.
5 0
3 years ago
Read 2 more answers
2 to the trird power plus 3 to third power - 3x4 - 5 to the seacond power divid by 5 plus (7x4)
zhenek [66]
I hope this helps ( there is no negatives )

5 0
3 years ago
Help me understand please​
erastova [34]

Answer:

V=pi x (r)^2 x h

V-volume r-radius h-height

V= pi x (3)^2 x 9

V= pi x 9 x 9

V= pi x 81

V= 254.47 (rounded)

6 0
3 years ago
Can someone please help me
salantis [7]

Using Pythagorean theorem

\\ \sf\longmapsto P^2=H^2-B^2

\\ \sf\longmapsto P^2=6^2-5^2

\\ \sf\longmapsto P^2=36-25

\\ \sf\longmapsto P^2=11

\\ \sf\longmapsto P=3.2

4 0
2 years ago
Read 2 more answers
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