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tia_tia [17]
3 years ago
6

What is the ratio of carbon to oxygen in the following balanced equation: 2C + O2–> 2CO

Chemistry
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer:

The ratio is 2:1, that is 2mol C  / 1mol O2

Explanation:

First check to see if the equation is balanced. It is so now let's find the ratio.

The ratio is the stoichiomeric coefficient of the element or compound.

Carbon : Oxygen

2C : 1 O2   , so 2:1 ..


NemiM [27]3 years ago
4 0

<u>Answer:</u> The mole ratio of carbon and oxygen in the given chemical reaction will be 2 : 1

<u>Explanation:</u>

Mole ratio is defined as the ratio of number of moles of the two substances taken into account or the ratio of their respective stoichiometric coefficients.

The given chemical equation follows:

2C+O_2\rightarrow 2CO

Moles of carbon atom = 2

Moles of oxygen gas = 1

Moles of carbon monoxide gas = 2

So, the mole ratio of carbon and oxygen = 2 : 1

Hence, the mole ratio of carbon and oxygen in the given chemical reaction will be 2 : 1

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2 years ago
Zn(s) + 2 HCl(aq) —&gt; ZnCl2(aq)
miv72 [106K]

Answer:

First write the balanced equation for the reaction of HCl with Zn (NOTE: the previous answer did NOT do this and thus obtained an incorrect answer)

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moles of H2 desired:  PV = nRT

n = PV/RT = (1 atm)(10L)/(0.0821 Latm/Kmol)(298K)

n = 0.409 mole H2 desired

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4 0
3 years ago
At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?
Anton [14]

Answer:

0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

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n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

8 0
3 years ago
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