Which sample of matter is a mixture? Air, water, ammonia

jeka94

94.20 g/3.16722 mL = 29.74 g/mL

The ratio of mass to volume is equal to the substance's density. Thus, 29.74 g/mL is the density of whatever substance it may be. Density does not change for incompressible matter like solid and some liquids. Although, it may be temperature dependent.

7 0

3 years ago

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Mike mixes two chemicals in a container. The container quickly becomes very hot.

Kipish [7]

The chemicals are reactive with one another

7 0

2 years ago

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An electron in a hydrogen atom has orbital quantum number l = 7. how many possible values of the magnetic quantum number ml coul

MA_775_DIABLO [31]

A total of 15 magnetic quantum values are possible.

<h3>What is a Magnetic quantum number?</h3>

One of the four quantum numbers that describe an electron's position in relation to the nucleus is its magnetic quantum number.

Between spin and azimuthal quantum numbers, the magnetic quantum number comes in third on the list. The electron is positioned in one of the various orbitals formed by the division of the subshells (such as s, p, d, and f). It specifies the spatial direction of an orbital of certain energy (n) and form (I). The number of orbitals in each subshell is given as 2+1, where is the azimuthal quantum number. We can determine the orbital in each sub-shell using that method.

We are aware that there are between -l and +l conceivable magnetic quantum numbers.

Here l = 7

Thus, the range of magnetic quantum numbers will be -7 to +7.

Thus, the magnetic quantum numbers are as follows:

-7, -6, -5, -4,-3,-2,-1, 0, 1,2,3,4, 5, 6,7

This opens up a total of 15 magnetic quantum numbers.

To learn more about Magnetic Quantum, visit:

brainly.com/question/24204727

#SPJ4

6 0

2 years ago

Please help!! i need the answer ASAP!

nirvana33 [79]

Answer:

23.34 %.

Explanation:

The percentage of water must be calculated as a mass percent.

We need to find the mass of water, and the total mass in one mole of the compound. For that we need to use the atomic masses of each element and take in consideration the number of atoms of each element in the formula unit.

Atomic masses of the elements:

Cd: 112.411 g/mol, N: 14.0067 g/mol, O: 15.999 g/mol, and H: 1.008 g/mol.

Mass of the formula unit:

Cd(NO₃)₂•4H₂O

mass of the formula unit = (At. mass of Cd) + 2(At. mass of N) + 10(At. mass of O) + 8(At. mass of H) = (112.411 g/mol) + 2(14.0067 g/mol) + 10(15.999 g/mol) + 8(1.008 g/mol) = 308.5 g/mol.

Mass of water in the formula unit:

mass of water = (4 × 2 × 1.008 g/mol) + (4 × 15.999 g/mol) = 72.0 g/mol.

So, the percent of water in the compound = [mass of water / mass of the formula unit] × 100 = [(72.0 g/mol)/(308.5 g/mol)] × 100 = 23.34 %

7 0

3 years ago

For each of the following pairs of complexes, identify which one you would predict to have the larger Δo value, and explain why.

mash [69]

Answer:

a) [Fe(H2O)6]3+

b) [Fe(CN)6]3−

c) [Ru(CN)6]3-

Explanation:

. [Mn(H2O)6]2+ or [Fe(H2O)6]3+

The both complexes are d5 complexes with the same ligand , water. Water is a weak ligand and note that Mn^2+ often have a crystal field stabilization energy of zero hence

[Fe(H2O)6]3+ will possess a greater ∆o value.

The splitting of d orbitals according to the crystal field theory depends on the;

i)geometry of the complex

ii) nature of the metal ion,

iii)charge on the metal ion,

iv) ligands that surround the metal ion.

When the geometry and the ligands are held constant, the order of crystal field splitting is as follows;

Pt4+ > Ir3+ > Rh3+ > Co3+ > Cr3+ > Fe3+ > Fe2+ > Co2+ > Ni2+ > Mn2+

[Fe(H2O)6]3+ or [Fe(CN)6]3−

[Fe(CN)6]3− will have a greater ∆o because the cyanide ion is a strong field ligand compared to water. A strong field ligand causes a greater splitting of the octahedral crystal field compared to a weak field ligand.

. [Fe(CN)6]3− or [Ru(CN)6]3-

[Ru(CN)6]3- will exhibit a greater crystal field splitting. Crystal field splitting increases with the second and third row transition elements when compared to the crystal field splitting of the first row transition elements. Note that, there is an increase of approximately 30%–50% in Δo on going from a first-row transition metal to a second-row metal and another 30%–50% increase on going from a second-row to a third-row metal when they have the same geometry and oxidation state.

4 0

3 years ago