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FrozenT [24]
3 years ago
6

Why is a solution that is 0.10M HCN and 0.10M LiCN considered a good buffer system?

Chemistry
1 answer:
const2013 [10]3 years ago
8 0
Because of the common ion effect. Adding a common ion decreases the solubility of the salt which is the intention of a buffer.
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Calculate ΔH o rxn for the following: CH4(g) + Cl2(g) → CCl4(l) + HCl(g)[unbalanced] ΔH o f [CH4(g)] = −74.87 kJ/mol ΔH o f [CCl
anzhelika [568]

Answer:  ΔH for the reaction is -277.4 kJ

Explanation:

The balanced chemical reaction is,

CH_4(g)+Cl_2(g)\rightarrow CCl_4(l)+HCl(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H(products)]-\sum [n\times \Delta H(reactant)]

\Delta H=[(n_{CCl_4}\times \Delta H_{CCl_4})+(n_{HCl}\times B.E_{HCl}) ]-[(n_{CH_4}\times \Delta H_{CH_4})+n_{Cl_2}\times \Delta H_{Cl_2}]

where,

n = number of moles

Now put all the given values in this expression, we get

\Delta H=[(1\times -139)+(1\times -92.31) ]-[(1\times -74.87)+(1\times 121.0]

\Delta H=-277.4kJ

Therefore, the enthalpy change for this reaction is, -277.4 kJ

4 0
3 years ago
Indicate the number of significant figures in the following measured numbers:
inysia [295]

Answer: a = 2 ; f = 5 ; b = 2 ; g = 2 ; c = 2 ; h = 2 ; d = 4 ; i = 5 ; e = 3 ; j = 7

Explanation: Some rules to follow while calculating sig figs is

1. If a number like 4500 is present, only two sig figs are counted, but none of the zeros are, but if 4500. has a decimal point present, then you should count all the numbers available.

2. If a number like .0005 is present, only count 5 as a sig fig, however if the number is .00050, count the 0 after the 5 in this example (this would then have two sig figs.

3 0
2 years ago
This chemical equation represents the burning of methane, but the equation is incomplete. What is the missing coefficient in bot
Zolol [24]
CH4+(x)O2=CO2 +(Y)H2O
C=1 +H=4 +O=? = C=1 +O=2+? +H=?
H=4>>Y=2
C=1 +H=4 +O=? = C=1 +O=(2+2) +H=4
C=1 +H=4 +O=4 = C=1 +O=4 +H=4
O=4>>X=2
CH4+(2)O2 =CO2 +(2)H2O

6 0
3 years ago
Read 2 more answers
Determine whether each molecule given below is polar or nonpolar. of2
sergejj [24]

Answer : The molecule OF_2 is a polar molecule.

Explanation :

Polar molecule : When the arrangement of the molecule is asymmetrical then the molecule is polar.

Non-polar molecule : When the arrangement of the molecule is symmetrical then the molecule is non-polar.

The given molecule is, OF_2

The electronegativities of oxygen and fluorine are different. The molecular geometry of OF_2 is bent. As, Fluorine is more elctronegative than the oxygen. So, the arrows putting towards the more electronegative element i.e, fluorine. These arrows do not balance each other. Due to this, the asymmetrical arrangement of these bonds makes the molecule polar.

Hence, the given molecule OF_2 is polar.

7 0
3 years ago
What does the electron sea model for metals suggest? A. valence electrons drift freely around the metal anions B. valence electr
Ainat [17]

The electron sea model for metals suggest that the valence electrons drift freely around the metal cations.

Answer: B

Explanation

The sea model of electron is used for describing the mechanism of metallic bonding.

The metallic bonding generally occurs between 2 or more metals leading to the formation of alloys.

According to electron sea model, the electrons which contributes to the metallic bond are mostly the valence electrons of the atoms, these valence electrons get de-localized and can move freely around the nuclei of other atoms.

Overall, it seems like nuclei of positive charge is surrounded by sea of negative electrons.  

5 0
3 years ago
Read 2 more answers
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