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FrozenT [24]
3 years ago
6

Why is a solution that is 0.10M HCN and 0.10M LiCN considered a good buffer system?

Chemistry
1 answer:
const2013 [10]3 years ago
8 0
Because of the common ion effect. Adding a common ion decreases the solubility of the salt which is the intention of a buffer.
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Explain ionization suppressants as applied to atomic spectrometry
levacccp [35]

An ionization suppressor is an alkali metal capable of preventing ionization, which can be used in atomic spectroscopy to determine matter composition.

<h3>What is ionization?</h3>

Ionization refers to the phenomena capable of converting neutral atoms/molecules to electrically charged atoms/ions.

Ionization is a process by which radiation (e.g., alpha, beta, gamma rays) can pass energy to inert matter.

Some examples of ionization suppressors include salts of alkali metals (for example, potassium), which can be used in atomic spectroscopy to determine matter composition.

Learn more about ionization here:

brainly.com/question/1445179

8 0
2 years ago
Saftey goggles are worn in the lab- ​
Harrizon [31]

Answer:

Yes

Explanation:

Is this a question or what?

4 0
3 years ago
how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0
3 years ago
All moons in our solar system are similar in appearance
Murrr4er [49]

Answer:

yes

Explanation:

because they are all the same revolving round the sun the colors only differ

7 0
3 years ago
What are colloids? any1 wanna talk​
ololo11 [35]

Answer:A colloid is a mixture in which one substance consisting of microscopically dispersed insoluble particles is suspended throughout another substance.

Explanation:

And yes I would love to talk

7 0
2 years ago
Read 2 more answers
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