Answer:
The density of helgas sample is 17.8 g/cm³.
Explanation:
Given that,
Mass of sample of Rowena = 5 gram
Density = 8.9 g/cm³
Mass of sample of helga = 10 gram
We need to calculate the volume of sample
Using formula of volume

Where, m = mass
= density
Put the value into the formula


We need to calculate the density of helgas sample
Using formula of density

Where, m = mass
V = volume
Put the value into the formula


Hence, The density of helgas sample is 17.8 g/cm³.
Answer:
the second stage of cell division. its between prophase and anaphase during the chromosomes become attached to spindle fibers.
Answer:
Explanation:
It depends on how this is done. If you raise the pressure, the nitrogen will disappear (liquify) and all that will be left will be the 21 % oxygen and the 1% argon.
The process is very complicated because the boiling point of nitrogen keeps on changing. The boiling point is unstable.
Answer:

Explanation:
Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

Where
is Henry's law constant.
Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.
Given initially:

Also, at sea level, we have an atmospheric pressure of:

Given mole fraction:

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

Then the equation becomes:

Solve for
:

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

Apply Henry's law using the constant we found:
