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a_sh-v [17]
3 years ago
13

Which body changes occur during adolescence?

Chemistry
2 answers:
cupoosta [38]3 years ago
6 0
The answer is C,growth spurts,puberty,& sexual maturity
timama [110]3 years ago
3 0

Answer:

C) Growth, spurts, puberty, and sexual maturity

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List two things you know about nonrenewable energy
Contact [7]
It is natural and u can't by it
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4 years ago
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How does the ribosome know the sequence of amino acids
Andreyy89

Answer:

The ribosome contains three grooves which are sites for the tRNA. The first codon is AUG, which is called a "start codon". ... So, the tRNA that has the anti-codon sequence of UAC carrying the amino acid Met bonds to the mRNA codon. Another tRNA bonds to the next codon in the next groove with the next amino acid

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3 years ago
What is 2n^2 rule ( of science)​
lozanna [386]

2n² rule:

This rule is used to determine number of electrons in particular shell.

n=1 means K shell

n=2 means L shell

n=3 means M shell

n=4means N shell

The first K shell can hold upto 2 electrons, L shell can hold up to 8, third M shell can hold up to 18and the fourth N shell can hold upto 32 electrons. This rule of arrangement of electrons according to the shell is known 2n2 rule where n means number of shell.

For example: There is one proton in the nucleus of hydrogen atom, which moves in K shell path. It has no neutron.

3 0
3 years ago
Question 5
Nonamiya [84]

Answer:

chemical change

Explanation:

burning and cooking are both chemical changes.

6 0
3 years ago
In the laboratory, a student combines 28.3 mL of a 0.489 M manganese(II) acetate solution with 12.5 mL of a 0.339 M manganese(II
Eddi Din [679]

Answer:

M = 0.441 M

Explanation:

In this case, we have two solutions that involves the Manganese II cation;

We have Mn(CH₃COOH)₂ and MnSO₄

In both cases, the moles of Mn are the same in reaction as we can see here:

Mn(CH₃COO)₂ <-------> Mn²⁺ + 2CH₃COO⁻

MnSO₄ <------> Mn²⁺ + SO₄²⁻

Therefore, all we have to do is calculate the moles of Mn in both solutions, do the sum and then, calculate the concentration with the new volume:

moles of MnAce = 0.489 * 0.0283 = 0.0138 moles

moles MnSulf = 0.339 * 0.0125 = 0.0042 moles

the total moles are:

moles of Mn²⁺ = 0.0138 + 0.0042 = 0.018 moles

Finally the concentration: 12.5 + 28.3 = 40.8 mL or 0.0408 L

M = 0.018 / 0.0408

M = 0.441 M

This would be the final concentration of the manganese after the mixing of the two solutions

7 0
4 years ago
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