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Sidana [21]
3 years ago
15

Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide wh

at lithium diorganocopper (Gilman) reagent is needed to convert 1-bromopropane into 1-pentene. Draw the structure of the organolithium compound that is used to prepare this Gilman reagent.
ether
2 R---- Li + Cul → R2CuLi
or THF
Chemistry
1 answer:
Cloud [144]3 years ago
5 0

Answer: sounds very confusing

Explanation:

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Wear _______________________ when handling batteries, because they can explode or leak.
Basile [38]

The answer is: b. Safety glasses and acid-resistant gloves.

Battery acid (sulfuric acid) has pH = 0.

Sulfuric acid (H₂SO₄) is a strong acid, it means that the solution of sufuric acid is more acidic (pH<7) than water (pH = 7).

Chemical dissociation of sulfuric acid in water:  

H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq).  

Sulfuric acid can come in contact with eyes and hands, so it is important to wear safety glasses and acid-resistant gloves.

4 0
3 years ago
What refers to the attractive forces that exist between molecules?​
CaHeK987 [17]
Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.
8 0
3 years ago
What changes occur in O + O = O2
ozzi

Answer:

They went from atoms to oxygen molecule.

Explanation:

I'm not sure if this is the answer your teacher is looking for, but in simple terms you had 2 oxygen atoms. Together they make an oxygen molecule, which is the stuff we breathe.

5 0
3 years ago
4. Which of the following NOT TRUE about real gas
Semenov [28]

Answer:

The answer is D.

Explanation:

Intermolecular force are negligible

When the distance between molecules decrease,

the attraction or repulsion become greater

7 0
2 years ago
You have a 28.2-g sample of a metal heated to 95.2°c. you drop it in a calorimeter with 100. g of water at 25.1°c. the final tem
Vlad [161]

The heat lost by the metal should be equal to the heat gained by the water. We know that the heat capacity of water is simply 4.186 J / g °C. Therefore:

100 g * 4.186 J / g °C * (31°C – 25.1°C) = 28.2 g * Cp * (95.2°C - 31°C)

<span>Cp = 1.36 J / g °C</span>

4 0
3 years ago
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