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Sidana [21]
3 years ago
15

Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide wh

at lithium diorganocopper (Gilman) reagent is needed to convert 1-bromopropane into 1-pentene. Draw the structure of the organolithium compound that is used to prepare this Gilman reagent.
ether
2 R---- Li + Cul → R2CuLi
or THF
Chemistry
1 answer:
Cloud [144]3 years ago
5 0

Answer: sounds very confusing

Explanation:

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Which form of asexual reproduction describes the process of a cell dividing to
stepan [7]

Answer:A

Explanation:Binary Fission, meaning ‘getting divided into half’ is a type of asexual reproduction where a single living cell grows twice its size and then splits to form two identical daughter cells, each carrying a copy of the parent cell’s genetic material. Examples of cells that use binary fission for division

3 0
3 years ago
Read 2 more answers
Select the ion.<br> -NO 2<br> -H2SO4<br> -AI +3
horrorfan [7]

Answer:

Al+3

Explanation:

Ion is a positively or negatively charged species. A neutral species does not carry any charge.

here only Al has +3 charge. So it is an ion.

6 0
3 years ago
What is the purpose of balancing chemical reactions?
Karo-lina-s [1.5K]

Answer: I believe its 1

Hope this helps!

4 0
2 years ago
A chemist is using 341 milliliters of a solution of acid and water. If 15.8% of the solution is acid, how many milliliters of ac
katen-ka-za [31]

Answer:

Volume of acid in the solution, 53.87 mL

Explanation:

This can be solved with a simple formula

(Volume of solution which is acid / Total volume) . 100 = % acid

(Volume of solution which is acid / 341 mL) . 100 = 15.8

Volume of solution which is acid / 341 mL = 0.158

Volume of solution which is acid = 0.158 . 341 mL

Volume of solution which is acid = 53.87 mL

8 0
3 years ago
The volume of a gas sample is 22.4 liters at STP. The density of the gas is 1.34 grams per liter.
lozanna [386]

Answer:

The mass of gas is 30.02 g.

Explanation:

Given data:

Volume of gas = 22.4 L

Density of gas = 1.34 g/L

Mass of gas = ?

Solution:

The given problem will be solved through density formula.

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

Now we will put the values in formula.

1.34 g/L = m /22.4 L

m = 1.34 g/L × 22.4 L

m = 30.02 g

The mass of gas is 30.02 g.

8 0
4 years ago
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