Like when a seed drops on the ground, and a bee come to take some honey. It sticks to the bee and where the bee goes, the bee will rub it off and the seed will start to grow.
Mostly the spyware and malware protection for desktop and laptop or workstations are to protected with anti-virus regular updates. All workstation or desktop or laptops are to updated operating systems patches.
If any operating systems patched update to be schedule and checked regularly. Schedule scanning by virus scanner to be made for desktop and laptop or workstations in regular interval basis
There are third parties tools such as malware and ADWCLEANER are also available free scanner software through internet where end user can download and scanner so software will clean the malware.
Mostly end user do mistake keep the files in desktop. Most of the malware software will affect the desktop folder only.
It will also affect c:\users folder and register enter keys.
Answer:
I think the best option would be C. Marked
Explanation:
hope this helps and sorry if it is incorrect.
Answer:
Answer
Explanation:
The only thing that is wrong with this code is the fact that the link is not completed (should be https://[link name].com/)
Other than that the code is fine
Answer:
Assumption: Only 1 job can be taken at a time
This becomes a weighted job scheduling problem.
Suppose there are n jobs
Sort the jobs according to fj(finish time)
Define an array named arr to store max profit till that job
arr[0] = v1(value of 1st job)
For i>0. arr[i] = maximum of arr[i-1] (profit till the previous job) or wi(weight of ith job) + profit till the previous non-conflicting job
Final ans = arr[n-1]
The previous non-conflicting job here means the last job with end timeless than equal to the current job.
To find the previous non-conflicting job if we traverse the array linearly Complexity(search = O(n)) = O(n.n) = O(n^2)
else if we use a binary search to find the job Complexity((search = O(Logn)) = O(n.Log(n))
