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kakasveta [241]
3 years ago
15

Consider Newton's Law of Universal Gravitation: FG= G (m1 m2)/d2 .

Physics
2 answers:
bixtya [17]3 years ago
7 0

Answer:

C

Mass is directly proportional to the Force of Gravity. If Mass increases, then the Force of Gravity increases; however, Distance is indirectly (or inversely) proportional to the Force of Gravity. If Distance increases, then the Force of Gravity decreases.

Explanation:

The formula for the force of gravity between two objects is

F=G\frac{m_1 m_2}{d^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

d is the separation between the two objects

We notice the  following:

- F is directly proportional to the masses, F\propto m_1, m_2. This means that if one of the masses increases, then the force between them, F, increases in a proportional way

- F is inversely proportional to the square of the distance, F\propto \frac{1}{d^2}. This means that if the distance between the two objects is increased, the force between them will decrease, and vice-versa.

So, the correct answer is

C

Mass is directly proportional to the Force of Gravity. If Mass increases, then the Force of Gravity increases; however, Distance is indirectly (or inversely) proportional to the Force of Gravity. If Distance increases, then the Force of Gravity decreases.

Citrus2011 [14]3 years ago
4 0

Answer:

C. Mass is directly proportional to the Force of Gravity. If Mass increases, then the Force of Gravity increases; however, Distance is indirectly (or inversely) proportional to the Force of Gravity. If Distance increases, then the Force of Gravity decreases.

Explanation:

According to the Newton's law of gravitation which states that, the force between between masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

Mathematically,

F ∝ Mm and F ∝ 1/d²

Where M and m are the masses

d is the distance between the masses

F = GMm and F = 1/d²

Since gravitational force is directly proportional to the masses, this means an INCREASE in the masses leads to INCREASE in gravitational force between them and vice versa.

Similarly, since the gravitational force is inversely proportional to the distance between them, this means that INCREASE in the distance leads to DECREASE in the gravitational force between them.

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Option C

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a care starting from rest has an acceleration 0.3 m/s square, calculate the velocity and distance travelled by this car after 2
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Answer:

Final velocity (v) = 36 m/s

Distance traveled (s) = 2,160 m

Explanation:

Given:

Initial velocity (u) = 0

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Find:

Final velocity (v) = ?

Distance traveled (s) = ?

Computation:

v = u + at

v = 0 + 0.3(120)

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Which sequence shows all the spectral colors of visible light arranged in an increasing order of their frequency? A. red, yellow
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Which of the following is responsible for the overall integration of the autonomic nervous system (ANS)?
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Explanation:

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I hope you find this information useful and interesting! Good luck!

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3 years ago
The earth has a mass of 5.98 × 10^24 kg and the moon has a mass of 7.35 × 10^22 kg. The distance from the centre of the moon to
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Answer:

F = 4.48N

Explanation:

In order to calculate the net gravitational force on the rocket, you take into account the formula for the gravitational force between two objects, which is given by:

F=G\frac{m_1m_2}{r^2}         (1)

G: Cavendish's constant = 6.674*10^-11 m^3kg^-1s^-2

r: distance between the objects

You have a rocket at the middle of the distance between Earth and Moon, then, you have opposite forces on the rocket.

If you assume the origin of a system of coordinates at the rocket position, with the Moon to the left and the Earth to the right, you have:

F=G\frac{M_em}{r_1^2}-G\frac{M_mm}{r_2^2}       (2)

Me: mass of the Earth = 5.98*10^24 kg

Mm: mass of the Moon = 7.35*10^22 kg

m: mass of the rocket = 1200kg

r1: distance from the rocket to the Earth = 3.0*10^8m

r: distance between rocket and Moon = 3.84*10^8m - 3.0*10^8m = 8.4*10^7m

You replace the values of the parameters in the equation (2):

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The net force exerted over the rocket is 4.48N

4 0
4 years ago
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