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3 years ago

14

Circus a path along which electric current flows how would changing the battery in a circuit from 9 V to 1.5 V most likely affec

t the circuit

2 answers:

irina [24]3 years ago

7 0

Yeah what he said

cirus

a

path

along

which

electric

Nimfa-mama [501]3 years ago

4 0

When we reduce the voltage in circuit from 9 volts from 1.5 volts the flow of the current will also get reduced in a circuit.

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What happens to the energy of a wave as it moves away from its source?

Eddi Din [679]

Answer:

As the particles move further away from their normal position (up towards the wave crest or down towards the trough), they slow down.

Explanation:

This means that some of their kinetic energy has been converted into potential energy – the energy of particles in a wave oscillates between kinetic and potential energy. Hope that this helps you and have a great day :)

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3 years ago

The Bill and Melinda Gates Foundation hires you as a consultant to determine how best to use $20 billion to save the world and m

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3 years ago

Read 2 more answers

0.8 mj of energy are used by a blender in 3 and a half minutes what is the power rating on the blender

solong [7]

Answer:

Power rating on the blender = 3809.52 Watts

Explanation:

We have expression for power equal to ratio of work and time,

Energy used by blender = Work done by electricity = 0.8 MJ = $0.8*10^6J=800000J$

Time of using blender = 3.5 minutes = 210 seconds

So power of blender = 800000/210 = 3809.52 Watts

Power rating on the blender = 3809.52 Watts

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4 years ago

A microwave oven operates with sinusoidal microwaves at a frequency of 2400 MHz. The height of the oven cavity is 25 cm and the

Degger [83]

Answer:

F = 2 × 10⁻³ N

Explanation:

Given:

frequency, f = 2400 MHz

Height, h = 25cm = 0.25 m

Area of the base, A = 30 cm x 30 cm = 900 cm² = 0.09 m²

Energy of the microwave, E = 0.50 mJ = 0.5 x 10⁻³ J

Now, the time taken by the wave from top to the base, t = h/c

here, c is the speed of the light

thus,

t = 0.25/(3 x 10⁸) = 8.33 x 10⁻¹⁰ s

The radiation pressure $P_r$ = Intensity/c

now, the intensity is given as:

I = Power/ area

also,

Power = Energy/ time = 0.5 x 10⁻³ J/8.33 x 10⁻¹⁰ s = 600000 W

thus,

I = 600000 W/ 0.09 m² = 6666666.6 W/m²

substituting the value in the formula for pressure due to radiation, we have

$P_r$ = 6666666.6 W/m²/(3 x 10⁸)

also

pressure = Force/ area

thus,

Force/ area = 6666666.6 W/m²/(3 x 10⁸)

or

Force (F) = (6666666.6 W/m² × 0.09 m²)/(3 x 10⁸)

or

F = 2 × 10⁻³ N

6 0

3 years ago

Read 2 more answers

Two identical billiard balls traveling at the same speed have a head-on collision and rebound. If the balls had twice the mass,

Vinvika [58]

Answer:

a) No difference

Explanation:

Since the billiard balls are identical , they have the same mass. Also they have the same speed

Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

where m= mass , vi= initial velocity , vf= final velocity

since m1=m2=m , vi1=vi2=vi

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

m * v i² = 1/2 m (v f1² +v f2² )

vi² = 1/2(v f1² +v f2² )

since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf

therefore

v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²

and thus

vi= vf

in conclusion, there is no difference in speed after the rebound

4 0

3 years ago