What is the volume of H2 at 0° C and 1.00atm pressure ( STP)

1 answer:

8 0

You have to find the number of moles of hydrogen gas produced when zinc and hydrochloric acid reacted. To do this you need to use the equation PV=nRT and solve for n.(n=PV/RT)
I would use 0.08206 atmL/molK For the gas constant so you need to convert 22°C into Kelvin, 748mmHg into atm, and 59.1mL into L.
22°C+273K=295K
748mmHgx(1atm/760mmHg)=0.984atm
59.1L=0.0591L
plugging everything in:
n=(0.0591Lx0.984atm)/(0.08206 atmL/molKx295K)
n=0.00240mol H₂
After finding the amount of hydrogen gas, you can find the volume of gas at STP by divide it by the molar volume of gas (22.4mol/L).
0.00240mol/22.4mol/L=1.07L H₂
The answer is 1.07L of hydrogen gas at STP was released from the reaction.
I hope this helps. Let me know if there was anything that was unclear to you.

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What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n

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<u>Answer:</u> The volume of permanganate ion (potassium permanganate) is 10.0 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of ferrous sulfate solution = 0.381 M

Volume of solution = 20.0 mL = 0.020 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol$

For the given chemical equation:

$5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O$

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = $\frac{1}{5}\times 0.00762=0.00152mol$ of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

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How many atoms are in 26.8 g Fe

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Answer:

2.881x10^23 atoms

Explanation:

From the studies of Avogadro's hypothesis, we discovered that 1mole of any substance contains 6.02x10^23 atoms.

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Molar Mass of Fe = 56g/mol

56g of Fe contains 6.02x10^23 atoms.