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Volgvan
3 years ago
5

Which material undergoes radioactive decay?

Chemistry
2 answers:
soldi70 [24.7K]3 years ago
4 0

Answer:

all for nothn ginin all

Explanation:

zhenek [66]3 years ago
4 0
All elements that have a half life
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The distribution of Na+ ions across a typical biological membrane is 10 mmol dm-3 inside the cell and 140 mmol dm-3 outside the
trasher [3.6K]

Answer :  The value of \Delta G^o across the membrane is 6.80 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln K_{eq}\\\\\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

where,

\Delta G^o = standard Gibbs free energy  = ?

R = gas constant = 8.314 J/K.mol

T = temperature = 37^oC=273+37=310K

K_{eq}  = equilibrium constant

C_{in} = concentration inside the cell = 10mmol.dm^{3-}

C_{out} = concentration outside the cell = 140mmol.dm^{3-}

Now put all the given values in the above formula, we get:

\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

\Delta G^o=-(8.314J/K.mol)\times (310K)\times \ln (\frac{10mmol.dm^{3-}}{140mmol.dm^{3-}})

\Delta G^o=6.80\times 10^{3}J/mol=6.80kJ/mol

Thus, the value of \Delta G^o across the membrane is 6.80 kJ/mol

8 0
3 years ago
How can the atomic number and mass number be used to determine the amount of each subatomic particle present in an atom of a giv
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A blood test shows clumps only in wells containing anti-A and anti-B antibodies. The Rhesus test was negative. Which is the corr
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I believe AB- unless I’m reading the question wrong.
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Based on the information that is given, which atom is the table ?
andriy [413]

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The one with the greatest mass would be the one that has the most things in the nucleus, protons and nutrons

Explanation:

3 0
3 years ago
How many atoms are in 4 Al2(SO3)3
scZoUnD [109]

There are 337.23 × 10²³ atoms in 4 moles of aluminum sulfite Al₂(SO₃)₃.

Explanation:

The questions ask how many atoms are in 4 moles of aluminum sulfite Al₂(SO₃)₃?

To answer this we use the Avogadro's number to devise the following reasoning:

if in        1 mole of Al₂(SO₃)₃ there are 14 × 6.022 × 10²³ atoms

then in  4 moles of Al₂(SO₃)₃ there are X  atoms

X = (4 × 14 × 6.022 × 10²³) / 1 = 337.23 × 10²³ atoms

Learn more about:

Avogadro's number

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