Answer:
q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.
Explanation:
The Specific Heat capacity of Lead is 0.128 
This means, increase in temperature of 1 gm of lead by
will require 0.128 J of heat.
Formula Used :

q = amount of heat added / removed
m = mass of substance in grams = 85.0 g
c = specific heat of the substance = 0.128
= Change in temperature
= final temperature - Initial temperature
= 10 - 200
= -
put value in formula
q = - 
On calculation,
q = - 2067.2 J
- sign indicates that the heat is released in the process
The relation between the elements electro negativity, atomic radius, and ionization energy levels.
Answer : The concentration of
is, 0.12 M
Explanation :
Using Henry's law :

where,
= concentration of
= ?
= partial pressure of
= 4.5 atm
= Henry's law constant = 
Now put all the given values in the above formula, we get:


Thus, the concentration of
is, 0.12 M
Answer:
#2 you multiply the numbers
Explanation:
Answer:
The answer in this question is show you made Sodium Hydroxide and Hydrogen Gas.In order to do the products of the reaction relate to the phenol red test and the splint test you need to show that you made Sodium Hydroxide and Hydrogen Gas. Show that you made Sodium Hydroxide and Hydrogen Gas so that the products of the reaction relate to the phenol red test and the splint test.