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storchak [24]
2 years ago
13

How much would $200 invested at 7% interest compounded annually be

Mathematics
2 answers:
lina2011 [118]2 years ago
4 0

Answer:

70dollars

Step-by-step explanation:

simple interest

Reptile [31]2 years ago
3 0

Answer:

It will be worth $280.51.

Step-by-step explanation:

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per years and t is the time the money is invested or borrowed for, in years.

In this problem:

We want to find A, when P = 200, r = 0.07, n = 1, t = 5

A = P(1 + \frac{r}{n})^{nt}

A = 200*(1 + \frac{0.7}{1})^{1*5}

A = 280.51

It will be worth $280.51.

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Mia's perents said that she can use a space in the yard that measures. 13 feet long by 9 feet wide for her wildflower garden. Wh
ikadub [295]
A = L * W
A = 13 * 9
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7 0
2 years ago
34 less than the product of 14 and an unknown number is 78
Lubov Fominskaja [6]
34 less than (-34) the product of (multiply) 14 (14) and an unknown (x) is (=) 78 (78)

-34+14 times x=78
14 times x=14x
14x-34=78
add 34 to both sides
14x=112
divide both sdies by 14
x=8
the number is 8
6 0
3 years ago
Read 2 more answers
Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker
LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

<u><em>Let X = Math scores on the SAT exam</em></u>

So, X ~ Normal(\mu=514,\sigma^{2} =118^{2})

The z score probability distribution for normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma} ~  N(0,1)

where, \mu = population mean score = 514

           \sigma = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

       P(455 < X < 573) = P(X < 573) - P(X \leq 455)

       P(X < 573) = P( \frac{X-\mu}{\sigma} < \frac{573-514}{118} ) = P(Z < 0.50) = 0.69146

       P(X \leq 2.9) = P( \frac{X-\mu}{\sigma} \leq \frac{455-514}{118} ) = P(Z \leq -0.50) = 1 - P(Z < 0.50)

                                                         = 1 - 0.69146 = 0.30854

<em>The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.</em>

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = <u>0.38292</u>

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0
3 years ago
The average number of people who attended football games at a stadium increased from 8000 people in the year 2005 to 12500 peopl
erastova [34]

Answer: 43.75%

Step-by-step explanation:

7 0
2 years ago
How do you solve and check x/4 = -5
Mashutka [201]

Rearrange x/4-(-5)=0

Simplify x/4

-5 = -5/1 = -5*4/4

x- (-5*4)/4 = x+20/4

x+ 20/4 = 0

x+20/4 * 4 = 0*4

The equation now takes the shape: x+20=0

subtract 20 from both sides of the equation: x=-20

Answer: x=-20

6 0
3 years ago
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