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meriva
3 years ago
12

5.00 of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 128

./gmol, is burned completely in excess oxygen, and the mass of the products carefully measured: product mass carbon dioxide 17.19g water 2.81g Use this information to find the molecular formula of X.
Chemistry
1 answer:
vitfil [10]3 years ago
6 0

Answer:C10H10

Explanation:

Use a balanced equation to determined quantity of carbon and hydrogen. Then use simple division to determine the empirical formula before the molecula formula

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The eletron pairs repel each other in a tetrahedral shape.
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A scientist discovers a deep bowl-like divot under the ocean off the coast of eastern Mexico that is many kilometers across. The
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its B

Explanation:

8 0
3 years ago
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PLEASE HELP IM SO CONFUSED How does potassium need to be modified either on site or in a factory to make it useful. This should
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Potassium is not found  free in nature but is found in the form of potash. Potash is the ore of potassium and this ore is mined from deep down the earth or can sometimes  be found on the surface. Potash was mostly formed as sea water receded and left deposits.

Potash is usually in the form of potassium salts such potassium chloride and  potassium sulphate.  The potash  is mined then taken to the factory where it is crushed and purified  by removing such impurities as clay.

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5 0
3 years ago
A solution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the b
Finger [1]
Answer : The molar mass of the solute will be 87.90 g/mol.

Explanation : We know the formula for elevation in boiling point, which is

Δt = iK_{b}m

given that, Δt = 0.357, K_{b} = 5.02 and mass of CCl _{4} = 40,

on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X10^{-3}. 
Now, 0.250/ 2.844 X10^{-3} = 87.90 g/mol. which is the weight of unknown component.
3 0
3 years ago
Calculate the moles and grams of solute in each solution. D. 2.0 L of 0.30M Na2SO4. I already have A, B, and C. Thanks!
e-lub [12.9K]
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol


Find the molar mass
2Na = 23 * 2 = 46 grams
1S   = 32 * 1 = 32 grams
O4   = 16 * 4 = 64 grams
Total =            142 grams / mol

Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???

given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams. 

85.2 are in a 2 L solution that has a concentration of 0.6 mol/L


4 0
3 years ago
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