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MAXImum [283]
2 years ago
15

If you were to conduct an experiment to answer the question, "Does the volume of a caffeinated drink affect your reaction time?”

, what would be the controlled variable?
A type of drink
B reaction times
C number of bubbles
D volume of caffeinated drink
Chemistry
1 answer:
Ann [662]2 years ago
4 0

Answer:

A Type of Drink

Explanation:

A controlled variable remains constant throughout the experiment.

In such experiment, you'd test the volume of one single caffeinated drink. You'd have to use the same type of drink every trial.

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Write at least three characteristics of acids and three characteristics of bases. These characteristics should be what makes the
ki77a [65]
Characteristics of acid

-It tastes sour
-It reacts with metals and carbonates
-It turns blue litmus paper red

Characteristics of base

-It tastes bitter
-It feels slippery
-It turns red litmus paper blue.
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3 years ago
Which of the following best states the difference between an alcohol and an ether?
goldenfox [79]
I'd say it would be
D 
8 0
3 years ago
When electrons gain energy, what can they do?
beks73 [17]

B. When electrons gain energy, they have the power to move up to a higher energy level in an atom.

3 0
4 years ago
A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

5 0
4 years ago
Combustion of coal releases sulfur dioxide into the atmosphere. The following process converts this gas into sulfuric acid, a co
Usimov [2.4K]

Answer:

m=7.07gH_{2}SO_{4}

Explanation:

1. Take in account the sulfuric acid at STP:

1840\frac{g}{L}

2. Density is expressed as the ratio between the mass and the volume of a substance so:

d=\frac{m}{V}

Solving for m:

m=\frac{V}{d}

3. Replace values:

m=\frac{1.30*10^{4}L}{1840\frac{g}{L}}

m=7.07gH_{2}SO_{4}

4 0
3 years ago
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