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shutvik [7]
3 years ago
5

5. What types of surfaces would result in greater friction?

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

<em>Rough </em><em>and </em><em>irregular</em><em> </em><em>surface</em>

<em>these</em><em> </em><em>surfaces</em><em> </em><em>tends </em><em>a </em><em>lot </em><em>of </em><em>friction</em><em> </em>

<em>but </em><em>on </em><em>smooth</em><em> </em><em>surface</em><em> </em><em>there </em><em>is </em><em>least </em><em>friction</em>

<em>hope</em><em> it</em><em> helps</em>

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A: 11 protons and 21 neutrons

Explanation:

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What is the molar mass of chcl3?
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Calling all chemists...please help me!  Ive attached a screen shot of the problem
Olin [163]
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6 0
3 years ago
A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase
Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

  • The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298}  = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

V_{2} = \frac{58752}{4023}\\\\

<h3>V₂ = 15 L </h3>

Therefore, the final volume of the gas is 15 L

Learn more: brainly.com/question/25547148

3 0
2 years ago
hurry please! avogadro's law relates the volume of a gas to the number of moles of gas when temperature and pressure are constan
DIA [1.3K]

Answer:

Option B. 4 moles of the gaseous product

Explanation:

Data obtained from the question include:

Initial volume (V1) = V

Initial number of mole (n1) = 2 moles

Final volume (V2) = 2V

Final number of mole (n2) =..?

Applying the Avogadro's law equation, we can obtain the number of mole of the gaseous product as follow:

V1/n1 = V2/n2

V/2 = 2V/n2

Cross multiply

V x n2 = 2 x 2V

Divide both side by V

n2 = (2 x 2V)/V

n2 = 2 x 2

n2 = 4 moles

Therefore, 4 moles of the gaseous product were produced.

5 0
3 years ago
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