The choices can be found elsewhere and as follows:
<span>A.The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice.. .
B.The enzyme pectinase enhances the taste of fruit juices, making them more popular.. .
C.The enzyme pectinase speeds up the breakdown of toxins in fruits, producing more juice.
The correct answer would be A. </span>The enzyme pectinase speeds up the breakdown of pectin in fruits, producing more juice. With this, the manufacturer company will get more volume of product from same amount of resource.
Those substances which has pH less than 5 are more acidic than Honeybee Venom. Some of them are listed below along with their pH scale,
1) <span>Acid rain and Tomato Juice has a pH of 4.
2) Soda and Orange Juice has a pH of 3.
3) Vinegar and Lemon Juice has pH of 2.
4) Gastric acid has a pH of 1.
5) Battery Acids have pH of zero.</span>
Sodium is a member of the alkali metal family with potassium (K) and Lithium (LI) sodium's big claim to fame is that it's one or two elements in your table salt. when bonded to chlorine (CI) THE two elements make sodium chloride
<u>Answer:</u> The value of
is 0.136 and is reactant favored.
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as ![K_{c}](https://tex.z-dn.net/?f=K_%7Bc%7D)
For the chemical reaction between carbon monoxide and hydrogen follows the equation:
![N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)](https://tex.z-dn.net/?f=N_2%28g%29%2B3H_2%28g%29%5Crightleftharpoons%202NH_3%28g%29)
The expression for the
is given as:
![K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
We are given:
![[NH_3]=0.25M](https://tex.z-dn.net/?f=%5BNH_3%5D%3D0.25M)
![[H_2]=0.75M](https://tex.z-dn.net/?f=%5BH_2%5D%3D0.75M)
![[N_2]=1.1M](https://tex.z-dn.net/?f=%5BN_2%5D%3D1.1M)
Putting values in above equation, we get:
![K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%280.25%29%5E2%7D%7B1.1%5Ctimes%20%280.75%29%5E3%7D)
![K_c=0.135](https://tex.z-dn.net/?f=K_c%3D0.135)
There are 3 conditions:
- When
; the reaction is product favored. - When
; the reaction is reactant favored. - When
; the reaction is in equilibrium.
For the given reaction, the value of
is less than 1. Thus, the reaction is reactant favored.
Hence, the value of
is 0.136 and is reactant favored.