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melomori [17]
3 years ago
11

I need help I can't chose between A or D

Chemistry
2 answers:
djyliett [7]3 years ago
7 0
That’s a hard one, but honestly i would go with a.
maria [59]3 years ago
7 0

Answer:

Increasing the temperature  

Step-by-step explanation:

Increasing the temperature gives the reacting molecules more kinetic energy.

More of the molecular collisions will have enough energy to get over the activation energy barrier and the reaction rate will increase.

B) is wrong. If you halve the amounts in the recipe for the experiment, the concentrations stay the same. There is no change in the rate of reaction.

C) is wrong. If you decrease the surface area of a solid, there will be fewer of its molecules at the surface to react. The rate of reaction will decrease.

D) is wrong. If you decrease the concentrations of the reactants, their molecules will be further apart. There will be fewer collisions per second, so the reaction rate will decrease.

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3 years ago
What is the molarity of 10g of carbon in a 500L solution?
Zolol [24]

Answer:

Molarity is the number of moles in a liter of a substance.

Molarity= Mole/volume

Mass= 10g

Molar mass of Carbon=12g

To calculate the mole we use the formula: mole= mass/molar mass

Mole = 10g/12g

Mole = 0.83

Molarity= 0.83/500 =0.0017moles per liter

5 0
3 years ago
How many milliliters of 4.00 M NaOH are required to exactly neutralize 50.0 milliliters of a 2.00 M solution of HNO3 ?
kramer

Answer: The volume of NaOH required is 25.0 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity HNO_3 = 1

M_1 = molarity of HNO_3 solution = 2.00 M

V_1 = volume of  HNO_3 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 4.00 M

V_1 = volume of  NaOH solution =  ?

Putting in the values we get:

1\times 2.00\times 50.0=1\times 4.00\times V_2

V_2=25.0ml

Therefore, volume of NaOH required is 25.0 ml

3 0
2 years ago
4. What type of evidence do you think would be most difficult to collect
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I think it is trace evidence since it is really small and hard to find.

3 0
3 years ago
Read 2 more answers
How many milliliters of 0.0630 m edta are required to react with 50.0 ml of 0.0110 m cu2 ?
gizmo_the_mogwai [7]
Moles Cu+2 = M * V
                     =  0.05 L * 0.011  m
                     = 0.00055 moles

when the molar ratio of Cu2+: EDTA = 1:1 so moles od EDTa also =0.00055 moles

and when the Molarity of EDTa = 0.0630 M

∴ Volume of EDTA =  moles / Molarity
                 = 0.00055 / 0.0630
                 = 0.0087 L = 8.7 L
4 0
3 years ago
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