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kari74 [83]
3 years ago
15

What is the slope? Pls answer

Mathematics
1 answer:
Ulleksa [173]3 years ago
3 0

Answer:

slope = difference in y / difference in x

slope = (9 - -9) / (9 -0)

slope = 18 / 9

slope = 2

Step-by-step explanation:

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Setler79 [48]

Answer:

diameter = 3,600 units

Step-by-step explanation:

Let \pi = 3.14

C = 2\pir

11,304 = 2(3.14)r

r = 1,800

d = 2r = 2(1,800) = 3,600

7 0
2 years ago
Someone help please thanks.
Lubov Fominskaja [6]

Answer:

t=x+44

Step-by-step explanation:

the x ounces are being added to the vase's pre-existing 44 ounces so therefore the equation is t=x+44

7 0
2 years ago
Surface area of the rectangular prism is 52 square inches. What is the volume
stepladder [879]
I don’t know at all lol
7 0
3 years ago
Show how to solve the following; answer must be with fractions and pi
Bess [88]

Answer:

3pi/4 and -pi/4

Step-by-step explanation:

We can simplify -6/6 to -1.

Therefore, this function can be simplified to arctan(-1).

Recall that the meaning of arctan is to find a value that will get the value inside the parenthesis when taken the tangent of it. In other words, tan(x) = -1.

Recall that tan(x) = sin(x)/cos(x). Now recall that sin(pi/4) and cos(pi/4) are both sqrt(2)/2, meaning that tan(pi/4) is 1. To make it -1, we can either make sin(x) -1 while keeping cos(x) 1, or the other way around.

If x is -pi/4, cos(x) will still be 1, but sin(x) will be -1, so tan(-pi/4) will be -1.

If x is 3pi/4, cos(x) will be -1, but sin(x) will still be 1, so tan(3pi/4) will be -1.

Side note: there are still infinite more answers. You can attain them by adding or subtracting 2pi as many times as you want from 3pi/4 or -pi/4 and still get an arctan of -1.

3 0
3 years ago
How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen
VashaNatasha [74]

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4

48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128

We can choose exactly three fives from five-card hands in 4C3*48C3 ways.

4C3*48C3=4*1128=4512

Therefore, 4512 five card hands contain exactly three fives.

4 0
3 years ago
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