Answer:
2.60 g of H₂ and 20.8 g of O₂ are produced in the decomposition of 23.44 g of water
Explanation:
Water decomposition is:
2H₂O → 2H₂ + O₂
We convert the mass of water, to moles:
23.44 g . 1 mol/18 g = 1.30 moles
Ratio is 2:2 with hydrogen and 2:1 with oxygen. Let's make rules of three:
2 moles of water can produce 2 moles of hydrogen gas and oxygen gas
Then, 1.30 moles will produce:
(1.30 . 2) /2 = 1.30 moles of H₂
(1.30 . 1) /2 = 0.65 moles of O₂
We convert the moles to mass
1.30 moles of H₂ . 2g / 1mol = 2.60 g of H₂
0.65 moles of O₂ . 32 g / 1 mol = 20.8 g of O₂
Answer:
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Explanation:
im confuzzled
Answer: ![5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is: [tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)](https://tex.z-dn.net/?f=5.6dm%5E3%5B%2Ftex%5B%20of%20gas%20is%20produced%20when%200.1%20moles%20of%20magnesium%20nitrate%20is%20decomposed.%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EExplanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EThe%20balanced%20chemical%20equation%20is%3A%0A%3C%2Fp%3E%3Cp%3E%5Btex%5D2NH_4NO_3%28s%29%5Crightarrow%202MgO%28s%29%2B4NO_2%28g%29%2BO_2%28g%29)
According to stoichiometry :
2 moles of 
produce = 4 moles of 
gas and 1 mole of 
gas
2 moles of produce = 5 moles of gas
Thus 0.1 mole of produce =
of gas
Volume of gas produced = 
Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.
Answer:
The mass of SO2 will be equal to the sum of the mass of S and O2.
Explanation:
This can be explained by the <em>Law of Conservation of Mass</em>. This law states that mass can neither be created nor destroyed. Knowing this, we can say that the reactants of a chemical reaction must be equal to the products.
In this case, the reactants Sulfur (S) and Oxygen (O2) must equal the mass of the product Sulfur Dioxide (SO2). Therefore, the statement <em>"The mass of SO2 will be equal to the sum of the mass of S and O2" </em>is correct.
