Calcium carbonate will be formed which is insoluble in water.
The answer is a) K and CrO4 only.
Answer:
[Co(NH₃)₄(H₂O)₂]³⁺: coordination number = 6.
[Cr(EDTA)]⁻: coordination number = 6.
[Pt(NH₃)₄]²⁺: coordination number = 4.
Na[Au(Cl)₂]: coordination number = 2.
Explanation:
In this complex, Co is bonded with 4 molecules of NH₃ (with 4 coordinate bonds, one bond for each molecule) and 2 molecules of H₂O (with 2 coordinate bonds, one bond for each molecule) forming the complex with 6 coordinate bonds.
∴ coordination number = 6.
In this complex, Cr is bonded with 1 molecules of EDTA (with 6 coordinate bonds, 4 O atoms and 2 N atoms in EDTA molecule).
∴ coordination number = 6.
In this complex, Pt is bonded with 4 molecules of NH₃ (with 4 coordinate bonds, one bond for each molecule).
coordination number = 4.
In this complex, Au is bonded with 2 atoms of Cl (with 2 coordinate bonds, one bond for each atom).
coordination number = 2.
0.042 moles of Hydrogen evolved
<h3>Further explanation</h3>
Given
I = 1.5 A
t = 1.5 hr = 5400 s
Required
Number of Hydrogen evolved
Solution
Electrolysis of water ⇒ decomposition reaction of water into Oxygen and Hydrogen gas.
Cathode(reduction-negative pole) : 2H₂O(l)+2e⁻ ⇒ H₂(g)+2OH⁻(aq)
Anode(oxidation-positive pole) : 2H₂O(l)⇒O₂(g)+4H⁻(aq)+4e⁻
Total reaction : 2H₂O(l)⇒2H₂(g)+O₂(g)
So at the cathode H₂ gas is produced
Faraday : 1 mole of electrons (e⁻) contains a charge of 96,500 C
![\tt mol~e^-=\dfrac{Q}{96500}](https://tex.z-dn.net/?f=%5Ctt%20mol~e%5E-%3D%5Cdfrac%7BQ%7D%7B96500%7D)
Q = i.t
Q = 1.5 x 5400
Q = 8100 C
mol e⁻ = 8100 : 96500 = 0.084
From equation at cathode , mol ratio e⁻ : H₂ = 2 : 1, so mol H₂ = 0.042
Answer 19.9g. I’ve took the test last week at my uncle randy’s house
Answer:
Ryobi P517 18V Lithium Ion Cordless Brushless 2,900 SPM Reciprocating Saw w/ Anti-Vibration Handle and Tool-Less Blade Changing
Explanation: