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borishaifa [10]
3 years ago
14

What is the pH of a 9.50×10−2 M ammonia solution??

Chemistry
1 answer:
Darina [25.2K]3 years ago
4 0
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻

c=9,50*10⁻² mol/L

Ammonia solution is a weak electrolyte.
The dissociation constant of ammonium hydroxide is:
K=1.78*10⁻⁵

[OH⁻]=√(Kc)

pH=14-pOH=14+lg[OH]⁻
pH=14+lg(√(Kc))

pH=14+lg(√(1.78*10⁻⁵*9.50*10⁻²))=8.23
pH=8.23
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Wood with a mass of 3.0 grams was burned in an open dish. The ashes weighed 1.2 grams.
mr_godi [17]

The rest of the wood was burned into gases of equivalent weight.

<u>Explanation</u>:

The rest of the wood was burned into gases of equivalent weight.

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What are two ways that atoms of different elements are different?​
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Multiple-choice questions have a special grading rule determined by your instructor. Assume that your instructor has decided to
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Answer:

The correct answer is option d.

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On submission of an incorrect answer to a multiple-choice question with n options,  we will lose:

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Which compounds are the Brønsted-Lowry bases in this equilibrium: HC2O4– + H2BO3– H3BO3 + C2O42– ?
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3 years ago
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A 75.0 mL 75.0 mL aliquot of a 1.70 M 1.70 M solution is diluted to a total volume of 278 mL. 278 mL. A 139 mL 139 mL portion of
Vlada [557]

Answer:

0.210 M

Explanation:

<em>A 75.0 mL aliquot of a 1.70 M solution is diluted to a total volume of 278 mL.</em>

In order to find out the resulting concentration (C₂) we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

1.70 M × 75.0 mL = C₂ × 278 mL

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<em>A 139 mL portion of that solution is diluted by adding 165 mL of water. What is the final concentration? Assume the volumes are additive.</em>

Since the volumes are additive, the final volume V₂ is 139 mL + 165 mL = 304 mL. Next, we can use the dilution rule.

C₁ × V₁ = C₂ × V₂

0.459 M × 139 mL = C₂ × 304 mL

C₂ = 0.210 M

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3 years ago
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