<span>Contar los átomos de cada elemento en los reactivos y los productos.
Utilizar coeficientes; Colóquelas en frente de los compuestos según sea necesario.</span>
No, why? Cause if you're winding up the clock it's basically doing what it needs to do. So there's no need for batteries.. I hope my sad sentence make sense :p
Answer:
3-methylhexane
Explanation:
you start counting from the longest chain to determine the correct name
5.6L of O2 means we have 0.25 moles of O2.
As, 1 mole has 6.023*10^23 molecules,
0.25 moles of O2 will have 0.25*6.023*10^23 molecules=1.50575*10^23 molecules
and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.
