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MrMuchimi
3 years ago
9

I'm sad to announce that this will most likely be my last day on brainly until next year, and to all the friends I've made on he

re from the last year, and to all the other people who've I've had amazing experiences with I would just like to say thank you.
This site has helped me greatly, and the majority of the people here on this platform are very helpful and friendly. I'll miss you all, and if I do return next year, I hope you all will be here too 。.:☆*:・'(*⌒―⌒*)))

- Eijiro <3
Chemistry
1 answer:
ohaa [14]3 years ago
3 0

Answer:

I know I never met you, but I'll miss you too. I hope you have a nice life. =)

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Answer:

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An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of
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Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the  alloy is 2.324 J/g°C

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