A sample of 4.5 moles of an unknown gas occupies a volume of 1.6L at 23.2atm, what is the ideal temperature in oC for this sampl
e of gas?
A student attempted to solve the above problem in the pic below, but made an error in the process. Identify the error or errors, solve the problem correctly, and provide the correct answer.
A student attempted to solve the above problem in the pic below, but made an error in the process. Identify the error or errors, solve the problem correctly, and provide the correct answer.
1 answer:
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Answer:
2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.
Explanation:
The balanced reaction is:
4 Fe + 3 O₂ → 2 Fe₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Fe: 4 moles
- O₂: 3 moles
- Fe₂O3: 2 moles
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
You can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe reacts with 3 moles of O₂, how much moles of Fe will be needed if 4.7 moles of O₂ react?
moles of O₂= 6.27
But 6.27 moles of Fe are not available, 5.4 moles are available. Since you have less moles than you need to react with 4.7 moles of O₂, iron Fe will be the limiting reagent.
So you can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, how many moles of Fe₂O₃ will be produced if 5.4 moles of Fe react?
moles of Fe₂O₃= 2.7 moles
Then:
<u><em>2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.</em></u>
Answer:
190 g
Explanation:
Knowing that:
- O₂ gas in air: 0.28 g O₂ / L of air
- Air inhaled at rest: 19.3 fl.oz. air / breath
- Human takes 20 breaths / min
The grams of oxygen gas (O₂) that a human at rest inhales in 1 hour (60 minutes) will be calculated as:
grams of O₂ = breaths in 1 hour * air inhaled per breath * amount of O₂ in air
grams of O₂ = 191.78 g
190 g of O₂ are inhaled in 1 hour (written in correct number of significant figures)
*In the calculation the amount of air inhaled per breath was converted from fl.oz. to Liters knowing that <em>1 L = 33.814 fl.oz.</em>
