The average atomic mass in amu of element X is 58.42 amu
The average atomic mass is the sum of the mass number of each of the isotopes multiplied by their respective abundances.
So;
The average atomic mass of element X is;
(58 * 0.68) + (60 * 0.26) + (0.06 * 62)
= 39.44 + 15.26 + 3.72
= 58.42 amu
The average atomic mass in amu of X is 58.42 amu.
Learn more: brainly.com/question/13292428
Definition - a small rocky body orbiting the sun
Sentence - asteroids are known to be in space
The specific heat capacity of copper metal : 0.390 J/g °C
<h3>Further explanation</h3>
Given
25 g metal
Δt metal = 18°C
15 g water
Δt water = 2.8 °C
Required
The specific heat capacity of copper metal
Solution
Q out = Q in
Q releases by metal = Q absorbed by water
m.c.Δt metal = m.c.Δt water(c water = 4.184 J/g °C)
25 x c x 18 = 15 x 4.18 x 2.8
c = 0.390 J/g °C
Answer:
The answer to your question is: 9 .43 ml of HNO3 70.3%
Explanation:
Data
Purity: 70.3%
density = 1.41g/ml
Volume = 1 l
Concentration = 0.12 M
Molecular weight = 1 + 14 + (16 x 3) = 63 gr
63 gr of HNO3 ------------------1 mol of HNO3 or IM
x ------------------- 0.12 M
x = 0.12M x 63 /1 = 7.65 g of HNO3
Now, calculate volume
density = mass / volume and volume = mass/density
volume = 7.65 / 1.41 = 6.63 ml of HNO3
Now, consider purity (it's and inver rule of three)
6.63 ml ----------------- 100%
x ----------------- 70.3 %
x = (6,63 x 100)/70.3 = 9.43 ml of HNO3
Water freezes at 0 degrees Celsius under normal conditions, the freezing point is the temp. at which a liquid becomes a solid.
