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OLga [1]
3 years ago
15

Most people use the _____ for intercity travel

Chemistry
2 answers:
EleoNora [17]3 years ago
4 0

Answer:

The person at the top said the right answer I checked

Lyrx [107]3 years ago
3 0
If your options are
train
subway system
domestic airports
private bus system

the correct answer is private bus system
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Define the word isotope​
sergeinik [125]

Answer:

Isotope, one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behaviour but with different atomic masses and physical properties.

7 0
3 years ago
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Convert 150 g/L to the unit g/mL.<br><br> 15,000 g/mL<br> 15 g/mL<br> 0.15 g/mL<br> 0.0015 g/mL
fredd [130]
1 g/L ------- 0.001 g/mL
150 g/L ----- ?

150 x 0.001 / 1

= 0.15 g/mL

Answer C
6 0
3 years ago
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Enough of a monoprotic weak acid is dissolved in water to produce a 0.0118 M solution. The pH of the resulting solution is 2.32
ser-zykov [4K]

Answer:

1.94 × 10⁻³

Explanation:

Step 1: Calculate the concentration of H⁺ ions

We will use the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.32 = 4.79 × 10⁻³ M

Step 2: Calculate the acid dissociation constant (Ka) of the acid

For a monoprotic weak acid, whose concentration (Ca) is 0.0118 M, we can use the following expression.

Ka = [H⁺]²/Ca

Ka = (4.79 × 10⁻³)²/0.0118 = 1.94 × 10⁻³

4 0
3 years ago
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA HELP
skad [1K]

Answer:

c

c

Explanation:

mark me brainliest pls

7 0
3 years ago
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Calculate the molality of a 10.0% by mass solution of NaCl ______ m
Lubov Fominskaja [6]

Answer:

\large \boxed{\text{0.180 mol/kg }}

Explanation:

Assume 100 g of solution.

Then you have 10.0 g of NaCl and 90.0 g of water.

\text{Molal concentration} = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}

1. Moles of NaCl

\text{Moles of NaCl} = \text{10.0 g NaCl} \times \dfrac{\text{1 mol NaCl}}{\text{58.44 g NaCl}} = \text{0.1711 mol NaCl}

2. Kilograms of water

\text{Kilograms} = \text{90.0 g} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{0.0900 kg}

3. Molal concentration

\text{Molal concentration} = \dfrac{\text{0.1711 mol}} {\text{0.0900 kg}} = \textbf{1.90 mol/kg}\\\\\text{The molal concentration of the solution is $\large \boxed{\textbf{0.180 mol/kg }}$}

5 0
3 years ago
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