Answer : The expected coordination number of NaBr is, 6.
Explanation :
Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.
This is represented by,
When the radius ratio is greater than 0.155, then the compound will be stable.
Now we have to determine the radius ration for NaBr.
Given:
Radius of cation, 
= 102 pm
Radius of cation, 
= 196 pm
As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.
The relation between radius ratio and coordination number are shown below.
Therefore, the expected coordination number of NaBr is, 6.
Answer:
C.) 3.5 atm
Explanation:
Because you are dealing with pressure and volume, you can use Boyle's Law to help you find the missing variable. The general formula looks like this:
P₁V₁ = P₂V₂
In this formula, "P₁" and "V₁" represent the pressure and volume of the chamber originally. "P₂" and "V₂" represent the final pressure and volume. You have been given the values of all the other variables but "P₂". Therefore, you can plug these values into the formula and simplify to find the final pressure.
P₁ = 1.5 atm
V₁ = 1.4 L
P₂ = ?
V₂ = 0.60 L
P₁V₁ = P₂V₂ <---- Boyle's Law formula
(1.5 atm)(1.4 L) = P₂(0.60 L) <---- Plug in values
2.1 = P₂(0.60 L) <---- Multiply 1.5 and 1.4
3.5 = P₂ <----- Divide both sides by 0.60
<span>The notation is not written in the correct order as the 4s subshell should appear before the 3d subshell.
</span>The correct order in an electron configuration would be:
1s , 2s , 2p , 3s , 3p , 4s , 3d , 4p , 5s , 4d , 5p , 6s , 4f , 5d , 6p ,..
So, for germanium the electronic configuration should be;
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p²
Answer:
The atom is oxidized is Ca.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- The oxidation process is the process in which electrons are lost and produce positively charged ions.
- The reduction process is the process in which electrons is gained and negatively charge ions are produced.
- In the reaction of chlorine with calcium:
<em>Ca + Cl₂ → CaCl₂,</em>
Ca loses 2 electrons and is oxidized to Ca²⁺. (Ca <em>→</em> Ca²⁺ + 2e).
Cl is gains 2 electrons in "Cl₂, oxidation state zero" and is reduced to Cl⁻. (Cl₂ + 2e <em>→</em> 2Cl⁻).
Polymer scientists have been trying to mimic this behavior by creating so called smart polymers. ... One of the most important classes of stimuli-responsive polymers used for controlled drug delivery is crosslinked polymer networks, e.g., hydrogels and microgels.
Hopefully this helps if not I’ll try rewriting it
