Answer:
The tension in string is found to be 188.06 N
Explanation:
For the vibrating string the fundamental frequency is given as:
f1 = v/2L
where,
f1 = fundamental frequency = 335 Hz
v = speed of wave
L = length of string = 28.5 cm = 0.285 m
Therefore,
v = f1 2L
v = (335 Hz)(2)(0.285)
v = 190.95 m/s
Now, for the tension:
v = √T/μ
v² = T/μ
T = v² μ
where,
T = Tension
v = speed = 190.95 m/s
μ = linear mass density of string = mass/L = 0.00147 kg/0.285 m = 5.15 x 10^-3 kg/m
Therefore,
T = (190.95 m/s)²(5.15 x 10^-3 kg/m)
<u>T = 188.06 N</u>
wait is this high school or middle or what??
Answer:
1.4 m/s
Explanation:
From the question given above, we obtained the following data:
Initial Displacement (d1) = 0.9 m
Final Displacement (d2) = 1.6 m
Initial time (t1) = 1.5 secs
Final time (t2) = 2 secs
Velocity (v) =..?
The velocity of an object can be defined as the rate of change of the displacement of the object with time. Mathematically, it can be expressed as follow:
Velocity = change of displacement /time
v = Δd / Δt
Thus, with the above formula, we can obtain the velocity of the car as follow:
Initial Displacement (d1) = 0.9 m
Final Displacement (d2) = 1.6 m
Change in displacement (Δd) = d2 – d1 = 1.6 – 0.9
= 0.7 m
Initial time (t1) = 1.5 secs
Final time (t2) = 2 secs
Change in time (Δt) = t2 – t1
= 2 – 1.5
= 0.5 s
Velocity (v) =..?
v = Δd / Δt
v = 0.7/0.5
v = 1.4 m/s
Therefore, the velocity of the car is 1.4 m/s
V = Volume of sample of gas = 1.00 L = 0.001 m³
T = temperature of the gas = 25.0 ⁰C = 25 + 273 = 298 K
P = pressure = 1.00 atm = 101325 Pa
n = number of moles of gas
using ideal gas equation
PV = n RT
101325 (0.001) = n (8.314) (298)
n = 0.041
n₁ = number of moles of helium
n₂ = number of moles of neon
m₁ = mass of helium = n₁ (4) = 4 n₁
m₂ = mass of neon = n₂ (20.2) = 20.2 n₂
given that :
m₁ = m₂
4 n₁ = 20.2 n₂
n₁ = 5.05 n₂
also
n₁ + n₂ = n
5.05 n₂ + n₂ = 0.041
n₂ = 0.0068
mole fraction of neon is given as
mole fraction = n₂ /n = 0.0068/0.041 = 0.166
P₂ = partial pressure of neon = (mole fraction) P
P₂ = (0.166) (1)
P₂ = 0.166 atm