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Maksim231197 [3]
3 years ago
12

Consider a reaction that has a positive ΔH and a positive ΔS. Which of the following statements is TRUE?A) This reaction will be

spontaneous only at high temperatures.B) This reaction will be spontaneous at all temperatures.C) This reaction will be nonspontaneous at all temperatures.D) This reaction will be nonspontaneous only at high temperatures.E) It is not possible to determine without more information.
Chemistry
1 answer:
Alja [10]3 years ago
4 0

Answer: A) This reaction will be spontaneous only at high temperatures

Explanation:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Using Gibbs Helmholtz equation:

\Delta G=\Delta H-T\Delta S

Given : \Delta H=+ve

\Delta S=+ve

\Delta G=(+ve)-T(+ve)

\Delta G=(+ve)(-ve)

Thus the value of  \Delta G  is negative and spontaneous when temperature is high.

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Afina-wow [57]

Answer:

<u>49 moles of atoms</u>

Explanation:

There are 7 individual atoms in each molecule of H2SO4:  (2 hydrogens + 1 sulfur + 4 oxygens).

Therefore, if 7 moles are decomposed, there would be 7 times that amount of individual atoms:

7 x 7 = 49 moles of atoms

4 0
2 years ago
How much heat is required to vaporize 43.9 g of acetone at its boiling point?
bogdanovich [222]
The heat required to vaporize 43.9 g  of acetone  at its boiling point is calculated as  below

 the heat of vaporization of acetone at its boiling  point is  29.1 kj/mole

find the moles of  acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles

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5 0
3 years ago
Read 2 more answers
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Ann [662]

Answer: The coefficients are 2, 2 and 1.

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The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for the given reaction is:

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3 0
2 years ago
A gas has a pressure of 5.7 atm at 100.0°C. What is its pressure at20.0°C (Assume volume is unchanged)
son4ous [18]

Answer:

\large \boxed{\text{4.5 atm}}

Explanation:

The volume and amount of gas are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

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p₂ = ?;          T₂ =  20.0 °C

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1. Convert the temperatures to kelvins

T₁ = (100.0 + 273.15) K = 373.15

T₂ =  (20.0 + 273.15) K = 293.15

2. Calculate the new pressure

\begin{array}{rcl}\dfrac{5.7}{373.15} & = & \dfrac{p_{2}}{293.15}\\\\0.0153 & = & \dfrac{p_{2}}{293.15}\\\\0.0153\times 293.15 &=&p_{2}\\p_{2} & = & \textbf{4.5 atm}\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{4.5 atm}}$}

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Answer:

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Explanation

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