Answer:
The answer to your question is -2855 J
Explanation:
Reaction
2C₂H₆ + 7O₂ ⇒ 4CO₂ + 6H₂O
Formula
Heat of reaction = ΔHrxn = ΣΔHrxn products - ΣΔHrxn reactants
Substitution
ΔHrxn = { 4(-393.5) + 6(-241.8)} - {2(-84.7) + 7(0)}
ΔHrxn = {-1574 -1450.8} - {-169.4}
ΔHrxn = -3024.8 + 169.4
ΔHrxn = -2855.4 J
Answer:
45 joules to calories= 10 (10.755258) calories
Below are the choices:
a. −166 kJ/mol
<span>b. 166 kJ/mol </span>
<span>c. 1.64 kJ/mol </span>
<span>d. 1.66 × 10^5 kJ/mol
</span>
To calculate the activation energy of a reaction, we use the Arrhenius equation. You may want to look it up to see how and why it works. In the problem you posted, there are two temperatures and two rate constants. After some rearranging and substitution of the Arrhenius equation, we have Ea = R T1 T2/(T1-T2) ln(k1/k2) = 8.314 J/mol K (600 K)(650 K)/(600 K-650 K) ln(2.7×10^-4 M^−1sec^−1/3.5×10^−3 M−^1sec^−1) = 166145 J/mol = 166 kJ/mol => choice b
The hypothesis would be that more green bugs would be found than bright red bugs because the green bugs are more camouflaged asunder the green plants than the bright red bugs.
Hello!
We have the following data:
v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15
P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K
<span>We apply the data above to the Clapeyron equation (gas equation), let's see:
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I hope this helps. =)