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xz_007 [3.2K]
3 years ago
9

What is the correct name for the compound H2O

Chemistry
2 answers:
Deffense [45]3 years ago
8 0

<u>Answer:</u>

The common name for the compound H2O is water.

<u>Explanation:</u>

The systemic name of H2O is Dihydrogen monoxide.

xz_007 [3.2K]3 years ago
8 0

Answer:

water

Explanation:

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What five things is the element carbon part of??
fgiga [73]

It is part of oceans, air, rocks, soil and all living things. Carbon doesn't stay in one place. It is always on the move! In the atmosphere, carbon is attached to oxygen in a gas called carbon dioxide.

Hope this helps.

7 0
3 years ago
What evidence of a chemical reaction might you see dropping an alka seltzer
aleksandrvk [35]
Bubbling if you put it in a liquid

3 0
3 years ago
. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r
Tom [10]

Answer :  The energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

Explanation : Given,

Wavelength = 435.8nm=435.8\times 10^{-9}m

conversion used : 1nm=10^{-9}m

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength = 435.8\times 10^{-9}m

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}

E=4.56\times 10^{-19}J

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

3 0
4 years ago
Permanganate ion reacts in basic solution with oxalate ion to form carbonate ion and solid manganese dioxide. Balance the skelet
saw5 [17]

Answer:

2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)

Explanation:

First, write the half equations for the reduction of MnO4^- and the oxidation of C2O4^2- respectively. Balance it.

Reduction requires H+ ions and e- and gives out water, vice versa for oxidation.

Reduction:

MnO4^- (aq) + 4H^+ (aq) + 3e- ---> MnO2(s) + 2H2O (l)

Oxidation:

C2O4^2- (aq) + 2H2O (l) ---> 2CO3^2 -(aq) + 4H^+ (aq) + 2e-

Balance the no. of electrons on both equations so that electrons can be eliminated. we can do so by multiplying the reduction eq by 2, and oxidation eq by 3.

2MnO4^- (aq) + 8H^+ (aq) + 6e- ---> 2MnO2(s) + 4H2O (l)

3C2O4^2- (aq) + 6H2O (l) ---> 6CO3^2 -(aq) + 12H^+ (aq) + 6e-

Now combine both equations and eliminate repeating H+ and H2O.

2MnO4^- (aq) + 8H^+ (aq) + 3C2O4^2- (aq) + 6H2O (l) --> 2MnO2(s) + 4H2O (l) +6CO3^2 -(aq) + 12H^+ (aq)

turns into:

2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)

5 0
4 years ago
The empirical formula of a compound is ch. it's molar mass is 52.07 g/mole. What is its molecular formula
Rina8888 [55]
For this item, we find first the mass of the compound with the empirical formula. That is,
                             molar mass = 12 (for C) + 1 (for H)
                                                   = 13 g/mole
Then, we divide the given mass of the molecular formula by the mass of the empirical formula. 
                                    n = 52.07 / 13 = 4
Therefore, the molecular formula is C₄H₄.
8 0
4 years ago
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