Answer:
0.17%
Explanation:
With the equation:
2Cr2O7 2- + C2H5OH + H2O --> 4Cr3+ + 2CO2 + 11H2O
We can assume that every mole of ethanol needs 2 moles of Dichromate to react.
So if in 1L we have 0.05961 moles of dichromate we can discover how many moles we have in 35.46mL
1000 mL - 0.05962 moles
35.46 mL - x
x = 
x = 2,11* 10^-3 moles
As we said earlier, 1 mole of ethanol needs 2 mole of dichromate, so in the solution we have 1,055*10^-3 moles of ethanol. We can discover the mass of ethanol present in the solution.
1 mole - 46g
1.055*10^-3 - y
y = 46 * 1.055*10^-3
y = 0.048 g
To discover the percent of alchol we can use a simple relation
28 g - 100%
0.048 - z
z = 
z = 0.17%
Answer: A. Diethyl ether has a very low miscibility in wate
The fact that the diethyl ether is miscible or not in water <u>does not imply a ris</u>k for the person who is working with this reagent in the laboratory.
However, the fact that diethyl ether forms explosive peroxides and that it is highly flammable implies that there is a risk of explosion when exposed to air and sunlight. On the other hand, as option C mentions, if a person inhales a large quantity of this reagent, they may lose consciousness and suffer some injury when fainting, due to the powerful anesthetic effect of this reagent.<u> In conclusion, options B, C and D are statements that imply safety problems associated with the use of diethyl ether in the laboratory, while option A does not imply it.</u>
Answer:
Mg₃N₂ (magnesium nitride)
Explanation:
M(total) = M(mg) + M (n)
M (n) = M(total) - M(mg)
= 0.433g - 0.313g
= 0.12g
mole (N) = 0.12g / 14.0067 g/mol
= 0.008567
mole Mg = 0.313g / 24.3050 g/mol
= 0.012878
Mg = 0.012878 / 0.008567
= 1.5
N = 0.008567 / 0.008567
= 1
multiply by 2 to get whole numbers
Mg = 1.5 × 2 = 3
N = 1 × 2 = 2
Mg₃N₂ (magnesium nitride)
Ksp of copper(II) hydroxide Cu(OH)2 is 4.9 x 10-8.
Chemical reaction (dissociation) of copper(II) hydroxide in water:
Cu(OH)2(s) → Cu²⁺(aq) + 2OH⁻(aq).
Ksp(Cu(OH)2) = [Cu²⁺]·[OH⁻]².
[Cu²⁺] = 2.42 x 10-3 mol/l; solubility od copper ions
[OH⁻] = 2[Cu²⁺] = 2 x 2.42 x 10-3 mol/l
[OH⁻] = 4.48 x 10-3 mol/l; solubility of hydroxide ions
Ksp = 2.42 x 10-3 mol/l x (4.48 x 10-3 mol/l)²
Ksp = 4.9 x 10-8
Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.
Solubility of the compound depends on the temperature of the solution and the structure of that compound.
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2.5LX2 M=5 moles
As Molarity X Volume= Total Number of Moles
