0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.
Explanation:
Data given:
volume of the nitrogen gas = 2 litres
Standard temperature = 273 K
Standard pressure = 1 atm
number of moles =?
R (gas constant) = 0.08201 L atm/mole K
Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law
PV = nRT
rearranging the equation to calculate number of moles:
PV = nRT
n = 
putting the values in the equation:
n = 
n = 0.091 moles
0.091 moles of nitrogen gas is contained in a container at STP.
Mass of vaporized triethylamine : 2.606 g
<h3>Further explanation</h3>
Given
0.5 L triethylamine
P = 18.5 psi
T = 25 °C
Required
mass of vaporized triethylamine
Solution
Conversion :
P 18.5 psi = 1,26 atm
T = 25 +273 = 298 K
Ideal gas law :
PV=nRT
n = PV/RT
Input the value :
n = (1.26 atm x 0.5 L) /(0.08205 x 298)
n = 0.0258
MW triethylamine = 101 g/mol
Mass triethylamine :
= n x MW
= 0.0258 x 101 g/mol
= 2.606 g
Answer:
i)a. P & R
b. Q& S
ii) R
iii) Atomic no & Atomic radius
2)a. C4H10
b. CH3Cl
Answer:
Periodic Properties of the Elements
Atomic Radius.
Ionization Energy (ionization potential)
Electron Affinity.
Electronegativity.
Metallic Character.
Other Trends.
Redox Potentials. Oxidation Potential. Reduction Potential.
Uses in knowing the Periodic Properties of Elements
Explanation:
Answer:
1. They will react.
2. 2HCI + Zn —> ZnCl2 + H2
Explanation:
1. From the question given above,
We can see that Zn is higher than H in the activity series.
NOTE: Elements higher (i.e at the top) in the activity series will displace those lower (i.e at the bottom) in the series. Thus, Zn is higher in the series than H. Therefore, Zn will displace H from solution. Hence, they will react.
2. The product obtained from the reaction can be seen as follow:
HCI + Zn —> ZnCl2 + H2
The above equation can be balance as follow:
There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:
2HCI + Zn —> ZnCl2 + H2
