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3 years ago

Animal growth rings are most common in:

2 answers:

6 0

I think the correct answer from the choices listed above is the last option. Animal growth rings are most common in aquatic animals. <span>Flatfish such as flounder and plaice can be aged from growth rings in bones found in the head called otholiths. Hope this answers the question.</span>

poizon [28]3 years ago

6 0

-----aquatic animals-----

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On a molar basis, which is a more effective bleaching agent- kbro3 or naocl?

Aleksandr-060686 [28]

<span>On a molar a basis, the most effective bleaching agent kbro3 has more oxygen, but due to the bromine, it would make things look yellowish. The bromine would counteracts the bleaching effect. As we all know, bleach is naocl or hypochlorite</span>

6 0

3 years ago

The microwaves in an oven are of a specific frequency that will heat the water molecules contained in food. (This is why most pl

statuscvo [17]

Answer:

2E-24

Explanation:

8 0

3 years ago

If 200 g of water is heated from 20 C to 40 C, then what is the heat added in kilocalories (same as food calories)?

Maslowich

Answer: 4Kcal

Explanation:

H= mcø

M=200g

C= 1 cal/g/°c

Ø= 40-20=20°c

H= 200*1*20= 4000calories= 4Kcal

8 0

3 years ago

Which element consists of positive ions immersed in a “sea” of mobile electrons

worty [1.4K]

Answer:

Explanation:

Nickel is the only metal listed. Metal elements have metallic bonds between the metal atoms. Positive metal ions in a sea of electrons.

4 0

2 years ago

If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated

Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:

$\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution

$\Delta T^o$ = freezing point of water

i = Van't Hoff factor

$K_f$ = freezing point constant

m = molality

$w_b$ = mass of solute

$w_a$ = mass of solvent

$M_b$ = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0

3 years ago