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MAVERICK [17]
3 years ago
5

Animal growth rings are most common in:

Chemistry
2 answers:
solniwko [45]3 years ago
6 0
I think the correct answer from the choices listed above is the last option. Animal growth rings are most common in aquatic animals. <span>Flatfish such as flounder and plaice can be aged from growth rings in bones found in the head called otholiths. Hope this answers the question.</span>
poizon [28]3 years ago
6 0

-----aquatic animals-----

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Which electron transition represents a gain of energy
Helen [10]

Answer:

The transition from lower energy level to higher energy level require a gain of energy.

Explanation:

When transition occur from lower energy level to higher energy level require a gain of energy. Electron could not jump unto higher energy level without gaining thew energy.

When electron jump into lower energy level from high energy level it loses the energy.

For example electron when jumped from 2nd to 3rd shell it gain energy and when in return back to 2nd shell from 3rd shell it loses energy.

The process is called excitation and de-excitation.

Excitation:

When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.

De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.

3 0
4 years ago
Can someone help me?
kupik [55]

Answer:

#1)2.23hrs

Explanation:

= 134/60

=2.23

=2.23hrs

4 0
3 years ago
The enthalpy of formation of xef2(g) is –108 kj mol–1 and the bond dissociation enthalpy of the f–f bond is 155 kj mol–1 . what
S_A_V [24]
Xe +f2 →Xef2
ΔXe = ΣB.P reactants - Σ B.d products
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-108 k.s/mol =155 k.s/mol - 2B.Dxe-f
263kJ/mol/2 = B. D xe-f
B.D xef = 131.5 kJ/mol
132 kJ/mol
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3 years ago
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The cubes have only the same volume, so the answer is c.
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the answer to this question is option A mark me as brainliest

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