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3 years ago

What is an ecosystem?

1 answer:

7 0

An ecosystem is a large community of living organisms (plants, animals and microbes) in a particular area. The living and physical components are linked together through nutrient cycles and energy flows. Basically where they live

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Why is atmospheric pressure much lower on the top of a mountain than it is as sea level?

Vika [28.1K]

Because the gravity levels decrese and so does the oxygen levels

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3 years ago

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Why is oxygen an element ? a it is essential to life b it burn c it combines with hydrogen d it cannot be broken down into a sim

MrRa [10]

D.) It cannot be broken down into a simple substance through chemical means...

5 0

3 years ago

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5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------> 1 Mg3(

professor190 [17]

Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

Hope this Helps!!!

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3 years ago

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Which is the name for the mixture of chemicals that forms as a gray brown haze in the atmosphere?

almond37 [142]

The answer is Smog, hope this helps! pls mark brainliest! thanks!

7 0

3 years ago

How much time would it take to distribute one avagadro's number of wheat grains if 10^10 grains are A)1.9*10^2 years B)1.9*10^10

Makovka662 [10]

Answer:

It takes 1.9 $\times 10^{6}$ years to distribute all the grains.

Explanation:

In one second, $10^{10}$ grains of wheat are distributed.

We are supposed to find the time it would take to Distribute Avogadro number of grains.

1 avogadro number = 6.022 $\times 10^{23}$

Number of grains distributed in 1 day = 86400 $\times 10^{10}$

= 8.64 $\times 10^{14}$

Number of grains distributed in 1 year= 8.64 $\times 10^{14} \times 365$

= 3.1536 $\times 10^{17}$

Time taken = $\frac{Number of grains to be distributed}{grains distributed in 1 year}$

= $\frac {6.022 \times 10^{23}}{3.1536\times 10^{17}}$

= 1.9 $\times 10^{6}$

7 0

3 years ago