Cr(PO4)2 = name the compound

A student was conducting an experiment designed to study the law of conservation of mass. The student measured the mass of all t

never [62]

562 grams because mass can not be created or destroyed

6 0

3 years ago

Use the chart to determine which type of bond is formed between potassium (K) and chlorine (Cl).

iris [78.8K]

Potassium and Chloride forms an ionic bond.
(K+) + (Cl-) = KCl

Potassium is under Group IA (Alkali Metal), wherein elements under this group can easily lose electrons.

Chlorine is under Group VII (Halogens), in which these elements can gain electrons easily.

The inner shell electrons on potassium will merge with the outer shell of electrons of chlorine to make potassium chloride.

6 0

3 years ago

Read 2 more answers

What is the molarity of a 250.0 ml aqueous solution of sodium hydroxide that contains 15.5 grams of solute?

Whitepunk [10]

The molar concentration of the solution is 1.55 mol/L.

1. Convert grams to moles.

$\text{Moles of NaOH} = 15.5 \text{g NaOH} \times \frac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{0.3875 mol NaOH}\\$

2. Convert millilitres to litres

$V = 250.0 \text{mL} \times \frac{\text{1 L}}{\text{1000 mL}} = \text{0.2500 L}\\$

3. Calculate the molar concentration (c)

$c = \frac{\text{moles}}{\text{litres}} = \frac{\text{0.2875 mol}}{\text{0.2500 L}} = \textbf{1.55 mol/L}$

3 0

3 years ago

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If 2.1 mL of 70.0% alcohol is added to 6.7 mL of water, what is the percent alcohol (%v/v) in the new mixture?

jok3333 [9.3K]

Answer:

Since we are adding more water to an alcohol solution,

the volume of alcohol in the alcohol will be the same but the volume percent of alcohol will decrease

Initial Volume of Alcohol in the solution:

We are given that 70% of the 2.1 mL solution is alcohol

So, Finding 70% of 2.1

70/100 * 2.1 = 1.470 mL alcohol

Volume of Water in the Solution:

In our initial solution, we have (2.1 - 1.47) mL water

and we add an additional 6.7 mL water in the solution

Hence,

the total amount of water in the solution = (2.1- 1.47) + 6.7

Total amount of water in the solution = 0.63 + 6.7

Total amount of water in the solution = 7.33 mL

Volume of the final solution = 8.8mL

Percent Alcohol in the new mixture:

Now that we know the volume of alcohol and the volume of water in our mixture, we can now find the percent composition of alcohol

Percent of alcohol (%v/v) = Amount of alcohol / 100mL of solution

Percent of alcohol = (1.47 / 8.8) * 100

Percent of alcohol = 0.167 * 100

Percent of alcohol = 16.7

Therefore, in a 100mL solution, we will have 16.7 mL alcohol

7 0

3 years ago

The standard free energy for the neutralization of hcl with naoh at 25 degrees c ic 79.9 kJ/mol. calculate the equillibrium cons

Nookie1986 [14]

According to Gibbs free energy and assume constant pressure (Helmholtz ΔG=ΔGΘ+RTln(K)Where K is the equilibrium constant.
At equilibrium ΔG=0:

0=ΔGΘ+RTln(K)→ΔGΘ=−RTln(K)

Solve for the equilibrium constant:

−ΔGΘRT=ln(K)[P][S]=K=exp(−ΔGΘRT)
using this equationJust put into the equation and calculate the equilibrium constant K.
hope it helps

4 0

3 years ago