Question is: how many 84s will fit in 5376? Let's think about some easy multiples:
84 * 100 = 8400, so it's too big
84 * 10 = 840, so it might work
84 | 5376 | 10
-840
84 | 4536 | 10
-840
84 | 3696 | 10
-840
84 | 2856 | 10
-840
84 | 2016 | 10
-840
84 | 1176 | 10
-840
84 | 336
We can't fit any more 840 in 336, so we check how many 84s are in 336 and what's the remainder:
84 | 336 | 4
- 336
So there's no remainder. Now we add all the partial quotients to get the final result:
10 + 10 + 10 + 10 + 10 + 10 + 4 = <u>64
</u>It's correct, I checked it with calculator. I just hope you'll be able to read something from that, it's quite difficult to do partial dividing with no pencil and paper :)
<span> x^2+8x+12 = </span>(x + 6)(x + 2)
Answer:
y=2x+8
Step-by-step explanation:
y=mx+b
M: cost for each ride, $2
B: Flat admission rate, $8
Alright first ranks doesn’t mean they’ll get it right. It just means how active the user is.
Now to answer your problem, c is given to be 0.5.
So 5(0.5) is the same as 5/2, which is 2.5.
So 10-2.5=7.5
They are the same length. You need to find the common denominator (8) and multiply both the numerator and denominator on 3/4 to ger 6/8. Than, just draw a numberline comparing the lengths! Hope this helped
