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Nata [24]
3 years ago
11

Which is one way to check out the answer to 129 ÷ 4 =30​

Mathematics
2 answers:
hjlf3 years ago
8 0

Answer:

idk

Step-by-step explanation:

you dont know

Lana71 [14]3 years ago
3 0
30*4=120 not 129

So if we use a calculator the correct answer is 32 1/4
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Select all the equations that describe this situation. Gino's backpack weighs 2 pounds less than Erik's backpack. Erik's backpac
scoray [572]
X + 2 = 14
and
x = 14-2
4 0
2 years ago
Mara's family is driving to her grandmothers' house. The family travels 239.4 miles between the hours of 9:10 a.M. To 1:40 p.M.
anzhelika [568]

Answer:

53.2 mph

Step-by-step explanation:

Mara's family travels 239.4 miles between the hours of 9:10 a.m. to 1:40 p.m.

1:40 p.m. is 13:40.

Thus, they traveled for

13 hours 40 minutes - 9 hours 10 minutes = 4 hours 30 minutes

that is 4\frac{1}{2}=4.5 hours.

Use formula:

D=r\cdot t,

where

D = distance

r = rate

t = time.

In your case,

D = 239.4 miles

t = 4.5 hours

Hence,

239.4=4.5r\\ \\r=\dfrac{239.4}{4.5}=53.2\ mph

5 0
3 years ago
Read 2 more answers
I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
What is the image of (-5, 6) after a reflection over the line y = -2
prohojiy [21]

Answer:

I'm pretty sure it would be (5,6)

Step-by-step explanation:

Reflecting a point over the Y-axis would change the x-coordinate, but not the y-coordinate

6 0
3 years ago
What is the constant proportionality of this problem
GaryK [48]
You did not include the problem therefore i cannot help you with this but if you could message me the problem i’d be happy too
8 0
3 years ago
Read 2 more answers
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