Question

What is the work done on a 30 kg object if a force of 15 N is applied for 5 seconds?

Answer 1

Answer:

Work done is 93.75J

Explanation:

Given mass, m = 30kg; Time = 5 seconds; force = 15N; u= 0

  Acceleration, a = F/m ⇒ 15/30

                                      ⇒   0.5ms

Displacement , s= ut+1/2at²

                    ⇒    0 +1/2 (0.5*5*5)

                    ⇒   0 + 1/2(0.5*25)

                    ⇒   0 + 1/2(12.5)

                   ⇒    0 + 6.25

                  ⇒      6.25m

 work done = Fs=15*6.25= 93.75 J