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Alex Ar [27]
3 years ago
8

Describe energy transformation and how it relates to the law of conversion of energy????

Physics
1 answer:
WINSTONCH [101]3 years ago
7 0
The law of conservation of energy<span> states that the total </span>energy<span> of an </span>isolated system<span> remains constant. </span><span>Energy can neither be created nor destroyed; rather, it transforms from one form to another. For instance, </span>chemical energy<span> can be </span>converted<span> to </span>kinetic energy<span> in the explosion of a stick of </span>dynamite<span>.</span>
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The spring is compressed a total of 3.0 cm, and used to set a 500 gram cart into motion. Find the speed of the cart at the insta
BartSMP [9]

Answer:

1.15 m/s

Explanation:

Part of the question is missing. Found the missing part on google:

"1. A hanging mass of 1500 grams compresses a spring 2.0 cm.   Find the spring constant in N/m."

Solution:

First of all, we need to find the spring constant. We can use Hooke's law:

F=kx

where

F=mg=(1.5 kg)(9.8 m/s^2)=14.7 N is the force applied to the spring (the weight of the hanging mass)

x = 2.0 cm = 0.02 m is the compression of the spring

Solving for k, we find the spring constant:

k=\frac{F}{x}=\frac{14.7}{0.02}=735 N/m

In the second part of the problem, the spring is compressed by

x = 3.0 cm = 0.03 m

So the elastic potential energy of the spring is

U=\frac{1}{2}kx^2=\frac{1}{2}(735)(0.03)^2=0.33 J

This energy is entirely converted into kinetic energy of the cart, which is:

U=K=\frac{1}{2}mv^2

where

m = 500 g = 0.5 kg is the mass of the cart

v is its speed

Solving for v,

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(0.33)}{0.5}}=1.15 m/s

4 0
3 years ago
I need help with this Physics problem. I've been stuck forever:
snow_tiger [21]
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3 years ago
A simple wheel and axle is used to lift a bucket of water out of a well. the radii of the wheel and axle are 20cm and 4cm, respe
Veronika [31]

Answer: i think it is A

Explanation: hope it helped

5 0
3 years ago
Read 2 more answers
A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
marta [7]

Answer:

(c)  As 'd' becomes doubled, energy decreases by the factor of 2

Explanation:

Energy stored in a parallel plate capacitor is given by:

U=\frac{1}{2}CV^2\\\\C=\frac{A\epsilon_{o}}{d}\\\\then\\\\U=\frac{1}{2}\frac{A\epsilon_{o}}{d}V^2--(1)\\\\

As capacitor remains connected to the battery so V remains constant. As can be seen from (1) that energy is inversely proportional to the separation between the plates so as 'd' becomes doubled, energy decreases by the factor of 2.

3 0
4 years ago
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the distriict record holding sprinter stars in the blocks and accelerates to 10/s in 20s what was the acceleration of the sprint
Mumz [18]
Acc= vf-vi/time=10-0/20= 0.5 m/s/s
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