Answer:
What does that even mean?
Explanation:
Answer:
Cannot see all the answer choices but, when pressure goes up, volume goes down. So your best bet is to choose the graph that has a downward slant.
Explanation:
Newton's three forces, normal, tension and friction, are present in a surprising number of physical situations
Newton's Laws, that describe the relationship between an obejct and the forces acting upon it, apply in almost every physical situation, from quantum mechanics to electricity.
The correct answer is:
Newton’s laws can explain the forces that occur between objects every day
Answer:
Newtons.
Explanation:
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
F represents force measured in Newton.
m represents the mass of an object measured in kilograms.
a represents acceleration measured in meter per seconds square.
Newtons is a measurement we use to determine the amount of force used to move an object by a simple machine. It is the International System of Units (SI) used to measure force and has a symbol of N.
Basically, it was named after Sir Isaac Newton based on his fundamental works in the field of mechanics (motions).
There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill:

- radius of the hill:

Solution:
(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car

(downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force,

, so we can write:

(1)
By rearranging the equation and substituting the numbers, we find N:

(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:

(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:

from which we find